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Sedbober [7]
3 years ago
15

Suppose a similar experiment was set up to measure changes in air composition immediately before and two days after twenty potte

d plants were placed in a clear, sealed aquarium near a window. Percentages of Chemicals in Air O2 CO2 Before 20.94% 0.03% After ? ? How would the second row of values in the plant experiment most likely compare to the second row of values in the original experiment? Oxygen levels would be higher, but carbon dioxide levels would be lower. Carbon dioxide levels would be higher, but oxygen levels would be lower. Oxygen levels would be higher, but carbon dioxide levels would be the same. Carbon dioxide levels would be higher, but oxygen levels would be the same. Mark this and return Save and Exit Next
Biology
2 answers:
Vika [28.1K]3 years ago
5 0

Answer:

The correct option is C: "Oxygen levels would be higher, but carbon dioxide levels would be the same".

Explanation:

The sealed aquarium is paced near a window which means they have access to sunlight, and hence, can photosynthesize. As the plants use up carbon dioxide during the day and give out oxygen during this process, they also respire during the night, a product of which is carbon dioxide. This is why the levels of carbon dioxide will remain the same and level of oxygen will rise because they are photosynthesizing for a longer period during the day than they are respiring during the night.

Hope that answers the question, have a great day!

Kisachek [45]3 years ago
5 0

Answer:

A

Explanation:

Oxygen levels would be higher, but carbon dioxide levels would be lower.

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