3 years ago

When crossing a street

Mathematics

2 answers:

Paul [167]3 years ago

5 0

C! youve got it dude !!!

NISA [10]3 years ago

3 0

Answer:

Step-by-step explanation:

Both A & B are correct

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Find the cost of painting a cubical block of side length 3.2 cm, if painting costs $5 per cm2.

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<h3><u>Answer</u>:- </h3>

$\longrightarrow \sf \$ \: 307.2$

<h3><u>Solution:-</u></h3>

Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-

$\green{ \underline { \boxed{ \sf{Surface \: area \:of \:Cube = 6a^2}}}}$

<u>where a is side of the cube </u>

$\begin{gathered}\\\quad \sf Surface \: area \:of \:Cube = 6\times(3.2)^2 \\\end{gathered}$

$\begin{gathered}\\\implies \quad \sf 6\times 3.2\times3.2 \\\end{gathered}$

$\begin{gathered}\\\implies \quad \sf 61.44 cm^2 \\\end{gathered}$

Now,

$\maltese \sf Cost \:of \:painting \: 1 \: cm² = \$ 5$

$\sf Cost \: of \: painting \: 61.44 \:cm²=61.44×5$

$\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2$

$\leadsto$ Thus it would cost $ 307.2 to paint the entire cubical block.

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