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Kazeer [188]
3 years ago
14

Find the common ratio of the geometric sequence 36, 6, 1, 16, ... . Write your answer as an integer or fraction in simplest form

.
Mathematics
1 answer:
nalin [4]3 years ago
7 0

Answer:

Step-by-step explanation:

The common ratio is the constant found by dividing any term by the previous term.

r=6/36=1/6

r=1/6

I am assuming the 16 at the end of the sequence was a typo. IF 16 was at the end of the sequence it is NOT a geometric sequence as there would not be a common ratio for all terms.

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Need geometry help ASAP please!
tatiyna

Answer:

1. 121 π  unit²

2. 143°

3. 151 unit²

Step-by-step explanation:

1.

Area of a circle is given by the formula  A = πr²

where

A is the area,

r is the radius of the circle

From the given diagram, we can see that the radius is 11, hence the area will be:

A=\pi r^2\\A=\pi (11)^2\\A=121\pi

The answer is  121\pi units^2

2.

The unshaded secctor and the shaded sector equals the circle. We know that circle is 360°. The unshaded sector has an angle of 217°. So the shaded part will be 360 - 217 = 143°

The measure of the central angle of the shaded sector is 143°

3.

Area of a sector is given by the formula  A=\frac{\theta}{360}*\pi r^2

Where

\theta is the central angle of the sector (in our case it is 143°)

r is the radius (which is 11)

Plugging in all the info into the formula we have:

A=\frac{\theta}{360}*\pi r^2\\A=\frac{143}{360}*\pi (11)^2\\A=150.99

<em>rounding to the nearest whole number, it is </em>151 units^2

3 0
4 years ago
If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting two queens and two kings.
Bingel [31]

<u>Given</u>:

If you are dealt 4 cards from a shuffled deck of 52 cards.

We need to determine the probability of getting two queens and two kings.

<u>Probability of getting two queens and two kings:</u>

The number of ways of getting two queens is 4C_2

The number of ways of getting two kings is 4C_2

Total number of cases is 52C_4

The probability of getting two queens and two kings is given by

\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}

Substituting the values, we get;

probability=\frac{4C_2 \cdot 4C_2}{52C_4}

Simplifying, we get;

probability=\frac{6 (6)}{270725}

probability=\frac{36}{270725}

probability=0.000133

Thus, the probability of getting two queens and two kings is 0.000133

7 0
3 years ago
Using the diagram below, what is the measure of ZE?
matrenka [14]

The measure of angle E is (b) 50°

<h3>How to determine the angle measure?</h3>

The given parameters are:

  • ΔCAB is similar to ΔCED
  • AB and ED are parallel

The similarity of the triangles implies that:

  • angle C = angle C
  • angle A = angle E
  • angle B = angle D

From the figure, we have:

angle A = 50

Substitute angle A = 50 in angle A = angle E

angle E = 50

Hence, the measure of angle E is (b) 50°

Read more about similar triangles at:

brainly.com/question/14285697

#SPJ1

7 0
2 years ago
What role does algebra/math have in DACA?<br><br> Plz I need it for a project !!<br><br> 30 points
Komok [63]
When someone is skilled in algebra and or math it opens up so many new career doors--Math and science jobs are highly sought out for. 
4 0
4 years ago
7*3=( *3)/(4*3)<br> Need to find the missing number before the *3
Butoxors [25]

Answer:

  the missing number is 84

Step-by-step explanation:

Let the missing number be represented by N. Then we have ...

  7*3 = N*3/(4*3)

Canceling common factors on the right, we have ...

  7*3 = N/4

Multiplying by 4 gives ...

  4*7*3 = N = 84

The missing number is 84.

3 0
4 years ago
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