All categories

4 years ago

A rectangular garden is 5 ½ yards long and 3 ¼ yards wide. What is the area, in square yards, of the garden?

Mathematics

1 answer:

Trava [24]4 years ago

8 0

Answer:

A = 17.875 or $17\frac{7}{8}$ yds²

Step-by-step explanation:

Take the length times the width to find the area

A = L x W

A = 5.5 x 3.25

A = 17.875 yds²

If this answer is correct, please make me Brainliest!

You might be interested in

Please help me with this I would give you 50 points.<br> FEET 1 4 5<br> INCHES 24 35

Harrizon [31]

Answer: feet: 1, 2, 3, 4, 5

inches: 12, 24, 36, 48, 60

Step-by-step explanation:

There are 12 inches in a foot, therefore if you have 1 foot you have 12 inches, if you have 2 feet you have 24 inches becauase 2*12 = 24 and so on...

3 0

2 years ago

Read 2 more answers

I need help with 16-18

klio [65]

16-18=-2
You can use a number line to help you.

3 0

4 years ago

Vineet solved a system of equations by substitution. In his work, he substituted an expression for one of the variables and solv

tester [92]

The system of equations does not have a solution.

For example, imagine these two equations y = x + 7 and y = x + 9

Now subsitute y in the second equation with the value from the first equation:

x + 7 = x + 9

x - x + 7 = 9

0 + 7 = 9

7 = 9.

That happens because the equations represent parallel lines, which do not have a common pair of points.

3 0

4 years ago

Read 2 more answers

A man is in a boat 2 miles from the nearest point on the coast. He is to go to point Q, located 3 miles down the coast and 1 mil

mafiozo [28]

Answer:

The answer is "0.45385".

Step-by-step explanation:

The time is taken to reach the coast $= \frac{\sqrt{(2^2 + x^2)}}{4}$

The time is taken to reach Q after reaching the coast $= \frac{\sqrt{(1 + (3-x)^2)}}{4}$

Total time, $T= \frac{\sqrt{(1 + (3-x)^2)}}{4}+ \frac{\sqrt{(1 + (3-x)^2)}}{4}$

This has to be minimum,

$\to \frac{dt}{dx} = 0$

$\to \frac{\sqrt{(2^2 + x^2)}}{2} + \frac{\sqrt{1 + (3-x)^2}}{3}\\\\ \frac{x}{4}\sqrt{(4+x^2)} + \frac{(x-3)}{(4\sqrt{(x^2-6x+10)}} = 0\\\\\frac{x^2}{16} \times (4+x^2) = \frac{(x-3)^2}{16 \times (x^2-6x+10)}\\\\x^2(4+x^2) = \frac{(x-3)^2}{(x^2-6x+10)}\\\\4x^2+x^4 = \frac{ x^2+9-6x}{(x^2-6x+10)}\\\\ 4x^2+x^4(x^2-6x+10) = x^2+9-6x\\\\4x^4-24x^3+40x^2+x^6-6x^5+10x^4= x^2+9-6x\\\\x^6-6x^5+ 14x^4-24x^3+39x^2+6x-9=0\\\\$

x=0.45385

6 0

3 years ago

How many ways can 4 people arrive at a party?

bonufazy [111]

We are going to name the people A, B, C, and D
1. A, B, C, then D
2. A, B, D, then C
3. A, C, B then D
4. A, C, D, then B
5. A, D, B, then C
6. A, D, C, then B
So at this rate, if there is 6 for the first letter, then there will be 6 for the others, so 6 x 4 = 24, so there are 24 different outcomes.
Hope this helped!

5 0

4 years ago