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sattari [20]
4 years ago
13

Vineet solved a system of equations by substitution. In his work, he substituted an expression for one of the variables and solv

ed for the value of the other. This resulted in the equation 7 = 9. What can Vineet conclude?
The solution to the system is (7, 9).
The system of equations does not have a solution.
The work must be incorrect because it is not possible to get this equation.
The system of equations has infinitely many solutions.
Mathematics
2 answers:
Mamont248 [21]4 years ago
7 0

Answer:

Step-by-step explanation:

The system of equations does not have a solution.

tester [92]4 years ago
3 0
The system of equations does not have a solution.

For example, imagine these two equations y = x + 7 and y = x + 9

Now subsitute y in the second equation with the value from the first equation:

x + 7 = x + 9

x - x + 7 = 9

0 + 7 = 9

7 = 9.

That happens because the equations represent parallel lines, which do not have a common pair of points.
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Consider this sequence
pochemuha
Hello,

u_{1} =1*(8-7)=1*(2*4-(6+1))\\
 u_{2} =2*(10-7)=2*(2*5-(6+2))=2*(2*(4+1)-(6+2))\\
 u_{3} =3*(12-9)=3*(2*6-(6+3))=3*(2*(4+2)-(6+3))\\
 u_{4} =4*(14-10)=4*(2*7-(6+4))=4*(2*(4+3)-(6+4))\\




u_{10}=10*(2*(4+10)-(6+10))\\
=10*(28-16)


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u_{n} =n*(2*(n+n-1)-(6+n))\\
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5 0
3 years ago
Which statement best describes the relationship between ABC and EDC?
sattari [20]
The first one
mecayse m3 is equal to 
8 0
3 years ago
Help me please hurry due today
xenn [34]

Answer:

23.025 square inches.

Step-by-step explanation:

To do this, we can split our polygon into 3 different shapes, a triangle, and 2 rectangles, and adding the areas of those 3 shapes together.

Specifically, triangle ABC, rectangle ACHI, and rectangle DEFG.

First we can start with the area of the triangle.

The area of a triangle is 1/2b*h. (1/2*base*height)

The base of the triangle AC, which is 4.2 inches. (9-4.8, Total length-DE)

The height is 2.75 inches. (6-3.25, Total height-AI)

Put it into the formual:

1/2*4.2*2.75=5.775

Next, I'm going to find the area of rectangle ACHI. The formula for the is just l*w (length*width)

The length is IH which is 4.2 inches. (9-4.8, total length-DE)

The width is AI which is 3.25 inches. (1.3+0.75+1.2, CD+EF+GH)

3.25*4.2=13.65

Now, we are going to find the area of rectange DEFG. Again, the formula is just l*w.

The length is DE which is 4.8 inches.

The width is EF which is 0.75 inches.

4.8*0.75=3.6

Now we add these areas together.

5.775+13.65+3.6=23.025

So the area of the model is 23.025 square inches.

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