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3 years ago

5

Marty's cat weighs 10.4 pounds. this is 24.4 pounds less than the weight of marty's dog. how much does marty's dog weigh?

1 answer:

Aleksandr-060686 [28]3 years ago

3 0

I hope this helps you

dogs-24,4=10,4

dog=34,8

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The necklace charm shown has two parts, each shaped like a trapezoid with identical dimensions. What is the total area, in squar

pashok25 [27]

The area of the trapezoid can be calculated through the equation,
A = (b₁ + b₂)h / 2
where b₁ and b₂ are the bases and h is the height. Substituting the known values from the given,
A = (25mm + 32mm)(15 mm) / 2
A = 427.5 mm²
Since there are two trapezoids in the necklace, the area calculated is to be multiplied by two to get the total area.
total area = (427.5 mm²)(2)
<em>total area = 855 mm²</em>

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4 years ago

Read 2 more answers

tia_tia [17]

2,700 / 12 = 225
225 / 5 = 45
They can make 45 necklaces.

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4 years ago

Find the product of<br> 2x^2(x + 3)

KengaRu [80]

Answer:

16x

Step-by-step explanation:

2x^2(x+3)

2 times 2 = 4

4x(x+3)

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3 years ago

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0

3 years ago

The next four digits in the number 0.3435363738394041 are

Vera_Pavlovna [14]

<h3>The pattern is 0.01+</h3>

<u>So the next 4 digits are:</u>

<h3>0.4243</h3><h3></h3>

0.34353637383940414243

3 0

3 years ago