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nalin [4]
3 years ago
14

If f(x) = x/2 -2 and g(x) = 2x^2 + x - 3, find (f+g) (x) A. 2x^2+3/2x +1 B. 2x^2+3/2x-5 C. x^2 - 6 D. 2X^2- x/2 + 1

Mathematics
1 answer:
Fed [463]3 years ago
5 0

Answer:

              \bold{(f+g)(x)=2x^2+\frac32x-5}

Step-by-step explanation:

f(x) =\frac x2-2\quad and\quad g(x) = 2x^2 + x - 3\\\\(f+g)(x)=f(x)+g(x)\\\\(f+g)(x)=\frac12x-2+2x^2+x-3\\\\(f+g)(x)=2x^2+\frac32x-5

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MrMuchimi

Answer:

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Step-by-step explanation:

I assume you mean 3x^2-6x-12=0.

First, note that you can divide both sides by 3. You get:

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3 years ago
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