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3 years ago

If f(x) = x/2 -2 and g(x) = 2x^2 + x - 3, find (f+g) (x) A. 2x^2+3/2x +1 B. 2x^2+3/2x-5 C. x^2 - 6 D. 2X^2- x/2 + 1

Mathematics

1 answer:

Fed [463]3 years ago

5 0

Answer:

$\bold{(f+g)(x)=2x^2+\frac32x-5}$

Step-by-step explanation:

$f(x) =\frac x2-2\quad and\quad g(x) = 2x^2 + x - 3\\\\(f+g)(x)=f(x)+g(x)\\\\(f+g)(x)=\frac12x-2+2x^2+x-3\\\\(f+g)(x)=2x^2+\frac32x-5$

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Answer:

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Step-by-step explanation:

<u>Given</u>:

$\sf \log_{10} 2 = 0.3010$

$\sf \log_{10} 3 = 0.4771$

To find log₁₀ 6, first rewrite 6 as 3 · 2:

$\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)$

$\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay$

$\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2$

Substituting the given values for log₁₀ 3 and log₁₀ 2:

$\begin{aligned} \sf \implies \log_{10}3+\log_{10}2 & = \sf 0.4771+0.3010\\ & = \sf 0.7781 \end{aligned}$

Therefore:

$\sf \log_{10}6=0.7781$

Learn more about logarithm laws here:

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