All categories

3 years ago

Find the linear equations written in standard form. Select all that apply. x + y = –1 –3x = y

Mathematics

1 answer:

Kryger [21]3 years ago

8 0

The correct answers are :

x + y = -1

x + 4y = 0

8x - 3y = 20

You might be interested in

A circle has a circumfernce of 13 it has a arc length of 11. What is the central angle of the arc in degrees

tatiyna

Answer: 304.6°

Step-by-step explanation:

First of all, using the circumference of the circle formula to find the radius of the circle.

Circumference of the circle = 13, ie

2πr = 13,

r = 13/2π ---------------------------- 1

Now getting the radius of the circle now, you now substitute for this in the formula for finding the length of an arc to get the central angle.

Arc length = 11 , ( 2πr0°/360) or (πr0°/180), so

πr0°/180 = 11 ------------------------ 2

Now solve for 0°, the central angle of the angle by making it the subject of the formula.

πr0° = 180 x 11

0° = 180 x 11

----------- ----------------- 3

πr

Now, put equation 1 in equation 3 and solve.

0° = 1980

--------

π x 13/2π

= 1980 x 2π

-----------

π.x. 13

= 1980 x 2

----------

= 3960/13

= 304.6°

Therefore, the central angle of the arc is 304.6°

Please be meticulous and understand the way I change the r in the denominator. It was the rule in fraction when dividing.

5 0

3 years ago

The base of a solid in the region bounded by the two parabolas y2 = 8x and x2 = 8y. Cross sections of the solid perpendicular to

Usimov [2.4K]

The two curves intersect at two points, (0, 0) and (8, 8):

$x^2=8y\implies y=\dfrac{x^2}8$

$y^2=\dfrac{x^4}{64}=8x\implies\dfrac{x^4}{64}-8x=0\implies\dfrac{x(x-8)(x^2+8x+64)}{64}=0$

$\implies x=0,x=8\implies y=0,y=8$

The area of a semicircle with diameter $d$ is $\dfrac{\pi d^2}8$ . The diameter of each cross-section is determined by the vertical distance between the two curves for any given value of $x$ between 0 and 8. Over this interval, $y^2=8x\implies y=\sqrt{8x}$ and $\sqrt{8x}>\dfrac{x^2}8$ , so the volume of this solid is given by the integral

$\displaystyle\frac\pi8\int_0^8\left(\sqrt{8x}-\dfrac{x^2}8\right)^2\,\mathrm dx=\frac{288\pi}{35}$

6 0

3 years ago

(a.) Vivian bought one bulb for $4. How many bulbs can Vivian buy if she has $128?

Shalnov [3]

Answer:

D because it’s D give me brainless

Step-by-step explanation:

8 0

2 years ago

What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?

Ipatiy [6.2K]

Answer:

$x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}$

Step-by-step explanation:

$2x^2 - 10x - 3 = 0 \\\\a = 2 \ , b = - 10 \ , \ c = - 3 \\\\x = \frac{-b^2\ \pm \ \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{10 \ \pm \sqrt{(-10)^2 - ( 4 \times 2 \times -3)} }{2 \times 2}\\\\x = \frac{10 \ \pm \sqrt{(100 - ( -24 )} }{4}\\\\x = \frac{10 \ \pm \sqrt{(100 + 24 } }{4}\\\\x = \frac{ 10 \ \pm \sqrt{124}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{4 \times 31}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{2^2 \times 31}}{4}\\\\x = \frac{ 10 \ \pm2 \sqrt{31}}{4}\\\\x = \frac{ 5 \ \pm\sqrt{31}}{2}\\\\$

$x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}$

3 0

2 years ago

IMAX theaters have the world’s largest screens. There are numerous IMAX theaters around the world. The Henry Ford Museum in Dear

SCORPION-xisa [38]

The dimensions would be 5 ft by 7 ft.

4 0

3 years ago

Read 2 more answers