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3 years ago

Please help if you can Thank you in advance:)

Mathematics

1 answer:

Radda [10]3 years ago

3 0

Answer:

Step-by-step explanation:

The diameter of the circle is the distance from the endpoint to another endpoint. The diameter of the given circle is segment PQ. To determine the diameter of the circle, we would apply the formula for determining the distance between two points on a straight line is expressed as

Distance = √(x2 - x1)² + (y2 - y1)²

Therefore,

Diameter = √(1 - - 3)² + (9 - 5)²

Diameter = √4² + 4² = √32

Radius = diameter/2 = √32/2

A circle is the set of all points in a plane equidistant from a fixed point called the origin or center.

The center of the circle is determined by applying the midpoint formula

(x1 + x2)/2, (y1 + y2)/2

= (- 3 + 1)/2, (5 + 9)/2

Center = (- 1, 7)

The formula for determining the equation of a circle us expressed as

(x - h)² + (y - k)² = r²

Where

r represents the radius of the circle

h and k represents the x and y coordinates of the center of the circle. Comparing with the given points,

h = - 1 and k = 7

Substituting into the formula, it becomes

(x - h)² + (y - k)² = r²

(x - - 1)² + (y - 7)² = (√32/2)²

(x + 1)² + (y - 7)² = 32/4

(x + 1)² + (y - 7)² = 8

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Garrrrryy <br><br> no need to show work <br> two questions <br> thankks

irakobra [83]

1. $x^2-x-72=0$
$\Delta=(-1)^2-4*1*(-72)=1+288=289$
$\sqrt{\Delta}=17$
$x_1=\frac{1-17}{2}=-8$
$x_2=\frac{1+17}{2}=9$

2. $f(x)=x^2+12x+20$
$\Delta=144-80=64$
$\sqrt{\Delta}=8$
$x_1=\frac{-12-8}{2}=-10$
$x_2=\frac{-12+8}{2}=-2$

8 0

4 years ago

Write 9x² - 36x = 4y² + 24y + 36 in standard form

Kisachek [45]

Answer:

9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;

(x - 2)²/2² - (y + 3)²/3² = 1

Step-by-step explanation:

The standard form of a hyperbola is given as follows;

(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1

The given equation is presented as follows;

9·x² - 36·x = 4·y² + 24·y + 36

By completing the square, we get;

(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)

(3·x - 6)² - 36 = (2·y + 6)²

(3·x - 6)² - (2·y + 6)² = 36

(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1

(3·x - 6)²/6² - (2·y + 6)²/6² = 1

3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1

(x - 2)²/2² - (y + 3)²/3² = 1

The equation of the hyperbola is (x - 2)²/2² - (y + 3)²/3² = 1.

5 0

3 years ago

Did I do this right?

Over [174]

Answer:

it must be yes!

Step-by-step explanation:

4 0

3 years ago

What pairs of angles in the figures below are verified angles

ankoles [38]

Answer: Option A and option B.

Step-by-step explanation:

By definition,t wo angles are vertical when they share the same vertex, this happen when two lines intersect each other. Therefore, they are opposite and equal.

The angles given in the options of the problem, whicht share the same vertex , are the following angles:

∠ATN and ∠RTD

∠BTD and ∠ATP

Then the answer is: Option A and option B.

6 0

3 years ago

PLEASE HELP!!! Needed ASAP!!

stiks02 [169]

Step-by-step explanation:

here is itt your answer............n

8 0

3 years ago