Question

Organize the following expressions from greatest to least by number of terms: x + 2xyz 3x + y + z 2x2y + x2 − 3x + 4 9x2yz

Answer 1

Expressions

(a) x + 2xyz: two terms

(b) 3x + y + z: three terms

(c) 3x^2 + x^2 - 3x + 4: four terms

(d) 9x^2yz: one term

The order, from greatest to least number of terms is (c), (b), (a) and (d)

Answer 2

Answer:

Step-by-step explanation:

The given expressions are:

$x+2xyz$, $3x+y+z$, $2x^2y+x^2-3x+4$ and $9x^2yz$.

We have to organize these expressions from greatest to least by number of terms.

The first expression that is $x+2xyz$ has two terms, second expression that is $3x+y+z$ has three terms, third expression that is $2x^2y+x^2-3x+4$ has four terms and the fourth expression that is $9x^2yz$ has one term, thus

Expressions from greatest to least by number of terms are:

$(2x^2y+x^2-3x+4) >(3x+y+z)>(x+2xyz)>(9x^2yz)$