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GenaCL600 [577]
3 years ago
6

A normal curve with a mean of 500 and a standard deviation of 100 is shown. Shade the region under the curve within one standard

deviation of the mean. How much of the data falls within the shaded region?

Mathematics
1 answer:
N76 [4]3 years ago
6 0

Answer:

And for this case we want to find how much of the data within the shaded region given in the figure attached.

And we can use the zscore formula given by:

z = \frac{X -\mu}{\sigma}

And if we find the z score for the limits we got:

z = \frac{400-500}{100}=-1

z = \frac{600-500}{100}= 1

And we want to find this probability using the normal standard distribution or excel:

P(-1

So we would expect about 68.2 % of the data within one deviation from the mean

Step-by-step explanation:

For this case we know that the variable of interest let's say x follows a normal distribution with the following parameters:

X \sim N(\mu = 500, \sigma =100)

And for this case we want to find how much of the data within the shaded region given in the figure attached.

And we can use the zscore formula given by:

z = \frac{X -\mu}{\sigma}

And if we find the z score for the limits we got:

z = \frac{400-500}{100}=-1

z = \frac{600-500}{100}= 1

And we want to find this probability using the normal standard distribution or excel:

P(-1

So we would expect about 68.2 % of the data within one deviation from the mean

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Evaluate. (15+12)2+310⋅5 Enter your answer as a mixed number in simplest form by filling in the boxes. $$
Sedbober [7]

Hey there!

(15+12)(2)+ 310(5)

= 27(2) + 310(5)

= 54 + 1,550

= 1,604

Therefore, your answer is should be: 1,604

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

8 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by
a_sh-v [17]

Answer:

Dimension of the box is 16.1\times 7.1\times 2.45

The volume of the box is 280.05 in³.

Step-by-step explanation:          

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is L=21-2h

The width of the box is W=12-2h

The volume of the box is V=L\times W\times H

V=(21-2h)\times (12-2h)\times h

V=(21-2h)\times (12h-2h^2)

V=252h-42h^2-24h^2+4h^3

V=4h^3-66h^2+252h

To maximize the volume we find derivative of volume and put it to zero.

V'=12h^2-132h+252

0=12h^2-132h+252

Solving by quadratic formula,

h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}

h=\frac{132\pm72.99}{24}

h=2.45,8.54

Now, substitute the value of h in the volume,

V=4h^3-66h^2+252h

When, h=2.45

V=4(2.45)^3-66(2.45)^2+252(2.45)

V\approx 280.05

When, h=8.54

V=4(8.54)^3-66(8.54)^2+252(8.54)

V\approx -170.06

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is L=21-2(2.45)=16.1

The width of the box is W=12-2(2.45)=7.1

So, Dimension of the box is 16.1\times 7.1\times 2.45

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3 years ago
Larry has $150 in his bank account. He deposits $27 and then writes a check for $96
IgorC [24]

Answer:

$-4

Step-by-step explanation:

Your welcome

5 0
3 years ago
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Kay scored above 90% on five of her math quizzes, 80% to 90% on fourteen of them, and 70% to 80% on two of them. What is the exp
Leya [2.2K]
In total, Kay took 5+14+2=21exams. she got 80%-90% on 14 of them. the probably is 14/21 which is 2/3. Therefore, the probability of Kay getting 80%-90% on her next exam is 2/3 or 66.6%
3 0
3 years ago
Can you please answer this question
Nat2105 [25]

Answer:

1. b

2. a

3. d

4. c

Step-by-step explanation:

3 0
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