Answer: Hence, the probability that he will get at least one lemon is 0.70.
Step-by-step explanation:
Since we have given that
Number of cars = 30
Number of lemon cars = 10
Number of other than lemon cars = 30-10 = 20
According to question, he bought 3 cars,
we need to find the probability that you will get at least one lemon.
So, P(X≤1)=1-P(X=0)=1-P(no lemon)
Here, P(no lemon ) is given by

so, it becomes,

Hence, the probability that he will get at least one lemon is 0.70.
Using logarithmic laws: log(a) + log(b) = log(ab)
log₄ (x + 9) + log₄ (x + 21) = log₄ [(x + 9)(x + 21)] = 3
Since we want the equation in terms of x, the next intuitive step is take 4 to the power of both sides, because the left hand side will simplify easily.



Solving the quadratic we get:



BUT, for the logarithmic equation to be defined, x > -9, so x≠ -25
Thus, the only solution is x = -5.
Answer:
10 and 42
Step-by-step explanation:
The difficulty with word problems is translating them into math.
Let's do that
---------------------
The sum of a number and two times a smaller number is 62.
let's call the bigger number b, and the smaller number s
b + 2s = 62
Three times the bigger number exceeds the smaller number by 116
3b = s + 116
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Now manipulate one of the equations to isolate the variable
3b = s + 116
Subtract 116 from both sides
3b - 116 = s
substitute for s = 3b - 116 in
b + 2s = 62
b + 2(3b - 116) = 62
Distribute
b + 6b - 232 = 62
combine like terms
7b = 294
Divide both sides by 7
b = 42
to find s plug in b = 42 into
b + 2s = 62
42 + 2s = 62
subtract 42 from both side
2s = 20
divide both sides by 2
s = 10