Answer:
B
Step-by-step explanation:
If the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Consider the first odd integer as x
Then the next consecutive odd integer = x+2
The 6 times the second integer= 6(x+2)
= 6x+12
Sum of an integer and 6 times the next consecutive odd integer is 61
Then the equation will be
x + 6x+12 = 61
Add the like terms in the equation
(1+6)x + 12 = 61
7x +12 = 61
Move 12 to the right hand side of the equation
7x = 61-12
7x = 49
x = 49/7
x = 7
The second number is
x+2 = 7+2
= 9
Hence, if the sum of an integer and 6 times the next consecutive integer is 61, the the value of lesser integer is 7
Learn more about equation here
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<span>4567876543345678765434678976543456876543*7576575675675*09*6865676*0*565545552651273652135*5272526*62526535*526242534546*786743165461354*653654264*751*1*5*7562756565464654+10 = 10
it took me awhile but that's what i got.
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Answer:
1/4 - (2/5 + (1/3 - (3 - 7/2) - 1/4) - 2/15)
= 1/4 - (2/5 + (1/3 - (6/2 - 7/2) - 1/4) - 2/15)
= 1/4 - (2/5 + (1/3 - (-1/2) - 1/4) - 2/15)
= 1/4 - (2/5 + (1/3 + 1/2 - 1/4) - 2/15)
= 1/4 - (2/5 + (4/12 + 6/12 - 3/12) - 2/15)
= 1/4 - (2/5 + (7/12) - 2/15)
= 1/4 - (2/5 + 7/12 - 2/15)
= 1/4 - (24/60 + 35/60 - 8/60)
= 1/4 - (51/60)
= 15/60 - 51/60
= -36/60
= -3/5
0.00000256 is the answer I got... I think it's correct! Hoped it help
