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4 years ago

When D is placed on this square, what will the perimeter of the square be?

Mathematics

1 answer:

Semmy [17]4 years ago

8 0

I can't see a square or a D given with your question.

But to find the perimeter you just have to add the surface of every side of the square.

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If g(x)=2(x-4), find the value of x if g(x)=20

Softa [21]

Answer:

32.64

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Is 2/3 greater than 7/8

Alborosie

2/3 = 0.66
7/8 = 3.38

- 7/8 is bigger because if you convert each of the fractions into decimals you will find your answer

- I hope this helps

7 0

4 years ago

Read 2 more answers

Write the recursive formula and the explicit formula for the sequence {-15,-7,1,9, 17,...}.

olchik [2.2K]

ANSWER

Explicit formula:

$a_n= 8n - 23$

Recursive

$a_{n}= a_{n - 1} + 8,a_1=-15$

EXPLANATION

The first term of the sequence is

$a_1=-15$

The common difference is

$d = - 7 - - 15$

$d = 8$

The nth term is given by the formula,

$a_n=a_1 + d(n - 1)$

$a_n= - 15+ 8(n - 1)$

$a_n= - 15+ 8n -8$

The explicit formula is;

$a_n= 8n - 23$

The recursive definition is

$a_{n}= a_{n - 1} + 8,a_1=-15$

5 0

4 years ago

Approximate the solution to the equation above using three iterations of successive approximation. Use the graph below as a star

n200080 [17]

Answer:

Step-by-step explanation:

<u>Approximate Roots of Functions:</u>

We are required to find the root of

$\displaystyle 5^{-x}+7=\ 2x+4$

Let's construct a function

$\displaystyle f(x)=\ 5^{-x}+7-2x-4$

Reducing:

$\displaystyle f(x)= 5^{-x}-2x+3$

The equation will have a solution when f(x)=0. We'll start from the approximate crossing point given in the graph (x=1.5)

$\displaystyle f(1.5)=5^{-1.5}-2(1.5)+3\ =0.089$

We'll move up on x=1.52

$\displaystyle f(1.52)=5^{-1.52}-2(1.52)+3=\ 0.046$

We are closer to the solution, let's try some more up

$\displaystyle f(1.54)=5^{-1.54}-2(1.54)+3=\ 0.0038$

This value x=1.54 is close enough to the solution of the original equation

From the options given, $\frac{25}{16}$ is the closest to our solution

$\boxed{Answer:\ x=25/16}$

8 0

4 years ago

Compute the multifactor productivity measure for each of the weeks shown for production of chocolate bars. What do the productiv

liq [111]

Answer:

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

Step-by-step explanation:

Computation for the multifactor productivity measure for each of the weeks shown for production of chocolate bars.

Using this formula

Week Multifactor productivity measure = (Output / Total Cost)

Where:

Output represent Quantity produced

Total cost represent Labor cost + Material cost + Overhead

Let plug in the formula

Week 1= 30,000/(40*12*6)+[(40*12*6)1.5]+(450*6)

Week 1 =30,000/(2,880)+(2,880*1.5)+2,700

Week 1 =30,000/(2,880+4,320+2,700)

Week 1=30,000/9,900

Week 1 =3.03

Week 2= 33,600/(40*12*7)+[(40*12*7)1.5]+(470*6)

Week 2 =33,600/(3,360)+(3,360*1.5)+2,820

Week 2=33,600/(3,360+5,040+2,820)

Week 2=33,600/11,220

Week 2 =2.99

Week 3= 32,200/(40*12*7)+[(40*12*7)1.5]+(460*6)

Week 3 =32,200/(3,360)+(3,360*1.5)+2,760

Week 3=32,200/(3,360+5,040+2,760)

Week 3=32,200/11,160

Week 3=2.9

Week 4= 35,400/(40*12*8)+[(40*12*8)1.5]+(480*6)

Week 4 =35,400/(3,840)+(3,840*1.5)+2,880

Week 4=35,400/(3,840+5,760+2,880)

Week 4=35,400/12,480

Week 4=2.83

Therefore the multifactor productivity measure for each of the weeks shown for production of chocolate bars is :

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

4 0

3 years ago