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Cerrena [4.2K]
3 years ago
12

Gaston has created a table regarding the ferret's results in the race. time (in seconds) distance (in feet) 2.5 01 Listed below

are the ferret's time in seconds and distance in feet covered. 10 10 22.5 15 40 20 Write out 3 ordered pairs that have time as the input, and distance as the output. 90 30 I 10 100 I 250 50 360 00 490 70​
Mathematics
1 answer:
LuckyWell [14K]3 years ago
6 0

Answer:

Step-by-step explanation:

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Eddi Din [679]

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3 years ago
1.What effect does replacing x with x−4 have on the graph for the function f(x) ?
Gwar [14]

Answer:

The absolute value wiill change

Step-by-step explanation:

Inserting different values in the absolute value can change the numerical value of the equation as a whole.

3 0
3 years ago
Read 2 more answers
Write a proportion for the statement.<br> 40 is to 10 as 32 is to 8.
Svetach [21]

Hi! ⋇

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  All proportions have <u>this</u> <u>form</u>:

  \sf{\dfrac{a}{b}=\dfrac{c}{d}}, Where \sf{\dfrac{a}{b}} is equal to \sf{\dfrac{c}{d}}.

 If \sf{\dfrac{a}{b}\neq\dfrac{c}{d}}, it's <u>not</u> a proportion.

_________________________

  Here we have two pairs of numbers:

40,10 and 32,8.

Written As a <u>proportion</u>, they <em>look like</em> :

\sf{\dfrac{40}{10}=\dfrac{32}{8}}

Hope this made sense to you :)

\it{Calligrxphy}

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6 0
1 year ago
Can someone please help me?
professor190 [17]

Answer:

correct 34324234324324

Step-by-step explanation:

8 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
wel

Answer:

z=\frac{15\sqrt{3}}{2}

Step-by-step explanation:

In leftmost triangle:

opposite side =y

adjacent=a

now, we can use trig formula

tan(60)=\frac{y}{a}

now, we can solve for y

y=atan(60)

In rightmost triangle:

adjacent=b

opposite=y

a+b=15

b=15-a

now, we can use trig formula

tan(30)=\frac{y}{15-a}

now, we can solve for y

y=(15-a)tan(30)

now, we can set them equal

and then we can solve for a

atan(60)=(15-a)tan(30)

\sqrt{3}a\cdot \:3=\frac{\sqrt{3}\left(15-a\right)}{3}\cdot \:3

4\sqrt{3}a=15\sqrt{3}

a=\frac{15}{4}

now, we can find b

b=15-\frac{15}{4}

b=\frac{45}{4}

now, we can use trig formula

cos(30)=\frac{b}{z}

now, we can find z

z=\frac{\frac{45}{4}}{cos(30)}

we can simplify it

and we get

z=\frac{15\sqrt{3}}{2}


4 0
3 years ago
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