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Blababa [14]
2 years ago
5

In a recent snail race,the winning snail traveled 5.85 cm 3/4 of a minute. How fast was the snail traveling in centimeters per s

econd?
Mathematics
2 answers:
Vladimir79 [104]2 years ago
6 0

Answer:

0.121 centimeters per second.

Step-by-step explanation:    

We are told that in a recent snail race,the winning snail traveled 5.85 cm 3/4 of a minute.

To find the speed at which snail was traveling in centimeters per second, we will divide 5.85 by number of seconds in 3/4 of a minute.

First of all we will find how many seconds are equal to 3/4 of a minute.

\text{3/4 of a minute}=(\frac{3}{4} \times 60)\text{ seconds}

\text{3/4 of a minute}=3\times 15\text{ seconds}

\text{3/4 of a minute}=45\text{ seconds}

Now we will divide 5.85 by 45 to find the speed of snail in centimeters per second.

\text{Speed of snail in centimeters per second}=\frac{5.85\text{ Centimeters}}{45\text{ Second}}

\text{Speed of snail in centimeters per second}=0.1211111111111111\frac{\text{ Centimeters}}{\text{ Second}}

Therefore, the snail was traveling at a speed of 0.121 centimeters per second.

tamaranim1 [39]2 years ago
3 0

Answer:

The snail traveling is 0.13 centimeters per second.

Step-by-step explanation:

Given : In a recent snail race,the winning snail traveled 5.85 cm 3/4 of a minute.

To find : How fast was the snail traveling in centimeters per second?

Solution :

The distance traveled is 5.85 cm.

The time taken is \frac{3}{4} minute.

Convert minute into second,

1 minute = 60 second

\frac{3}{4} minute = \frac{3}{4}\times 60 second

\frac{3}{4} minute = 45 second

The speed i.e. fast was the snail traveling in centimeters per second is given by,

\text{Speed}=\frac{\text{Distance}}{\text{Time}}

\text{Speed}=\frac{5.85}{45}

\text{Speed}=0.13

Therefore, the snail traveling is 0.13 centimeters per second.

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