6636 has 3 circle so 6636=3
8118 has 4 circle so 8118=4
2212 has 0 circle so 2212=0
8688 has 7 circle 8688=7
5971 has 1 circle 5971=1
.....Jeremy did not make a good inference. The ratio is not in proportion to 2/15. The correct inference would be about 26 students who did not read any books in July. The sample might be biased since it was limited to those at the pool....
It's the second one for sure
Answer:
π
2
,
3
⋅
π
2
,
3
⋅
π
4
,
7
⋅
π
4
Explanation:
Factorizing your equation we get
cot
(
x
)
=
0
so
cos
(
x
)
=
0
we get the following Solutions in the given interval
x
=
π
72
or
x
=
3
π
2
for the second case we get
cot
(
x
)
=
−
1
so
cos
(
x
)
=
−
sin
(
x
)
and we get
x
=
3
π
4
or
x
=
7
π
4
Hint:
To get the Solutions of the last equation you can use
√
sin
(
x
+
π
4
)
=
0
Step-by-step explanation:
The answer would be 57 with a remainder of 7.
