All categories

3 years ago

If tan theta =3/4 and the terminal point determined by theta is in quadrant 3, then:

Mathematics

2 answers:

Veronika [31]3 years ago

6 0

Answer:

cos theta= - 4/5

csc theta= - 5/3

cot theta= 4/3

Step-by-step explanation:

nasty-shy [4]3 years ago

3 0

The angle is 270° - arc tan(3/4) = 270° - 36.87° 233.13°.

You might be interested in

3m - (7m+12) =2 (m-3)

viktelen [127]

Remove parentheses
3m - 7m+12 = 2 m-3

collect like terms
3m-7m-12 = 2m-6

move terms
-4m - 12 = 2m-6

collect the like terms and calculate
-4m-2m = -6+12

divide both sides by -6
-6m=6

m= -1

7 0

3 years ago

M is the midpoint of AB and C is the midpoint of AM . Let the coordinate of A = 7y and the coordinate of B = 3x. Find the coordi

xz_007 [3.2K]

Answer:

The answer is below

Step-by-step explanation:

The coordinate of the midpoint of a line is gotten by adding the values of the two end points and then dividing the result by 2.

Given that M is the midpoint of AB, A = 7y and B = 3x, hence the coordinate of point M is given as:

M = (A + B)/2 = (7y + 3x)/2

Also, C is the midpoint of AM, hence the coordinates of point C is given as:

$C=\frac{A+M}{2}\\ \\C=\frac{7y+\frac{3x+7y}{2} }{2}\\ \\C=\frac{\frac{14y+3x+7y}{2} }{2}\\ \\C=\frac{21y+3x }{4}$

Hence the coordinates for point C is $C=\frac{21y+3x }{4}$

7 0

3 years ago

Which is equivalent to (−2m + 5n)2, and what type of special product is it?

Verdich [7]

4m^2-20mn+25n^2, a perfect square trinomial

5 0

3 years ago

Read 2 more answers

Suppose that F(x) = x2 and G(X) = 2/3 x^2. Which statement best compares the graph of G(x) with the graph of F(x)?

masha68 [24]

<h2>Answer:The graph of $G(x)$ is the graph of $F(x)$ compressed vertically.</h2>

Step-by-step explanation:

Given that $F(x)=x^{2}$ and $G(x)=\frac{2}{3}x^{2}$

$F(x)$ is always positive because $x^{2}$ is always positive.

$G(x)$ is always positive because $\frac{2}{3}x^{2}$ is always positive.

So,both are always positive.

So,there is no flipping over x-axis.

In $F(x)$ ,the height of a point at $x_{0}$ is $x_{0}^{2}$

In $G(x)$ ,the height of a point at $x_{0}$ is $\frac{2}{3}x_{0}^{2}$

So,height of any point has less height in $G(x)$ than $F(x)$

So,the graph of $G(x)$ is the graph of $F(x)$ compressed vertically.

3 0

3 years ago

What is the form of the Difference of Squares identity ? A. a ^ 2 - b ^ 2 = (a - b)(a - b) B. a ^ 2 + b ^ 2 = (a - b)(a - b); a

lozanna [386]

A^2 - b^2 = (a-b)(a+b)
To test it, expand the right hand side.

7 0

3 years ago