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Tpy6a [65]
2 years ago
6

Juanita wrote 3*7 as 3*40+3*7. What property did Juanita use to rewrite this expression?

Mathematics
1 answer:
GREYUIT [131]2 years ago
7 0
Distributed property
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Consider the diagram.<br> What is the length of segment AB?
Vlad [161]
The answer would be B
6 0
2 years ago
To solve the equation x ^2 - 2x = 3 by the technique of completing the square, you would add 4 to each side of the equation as o
Karolina [17]

Answer:

x = -1

x = 3

Step-by-step explanation:

\sf x^2 - 2x = 3

Add 1 to both sides:

\sf \implies x^2 - 2x+1 = 3+1

Factor the left side:

\sf \implies (x-1)^2 = 4

Square root both sides:

\sf \implies x-1 = \pm2

Therefore:

\sf \implies x-1=-2 \implies x=-1

\sf \implies x-1=2 \implies x=3

6 0
2 years ago
A: x/8=3/4<br> B: 2/5=x/40<br> C: 1/8=x/40<br> D:x/10=12/15
Aloiza [94]
I’m assuming you want to figure out what x is in the equation so....

6/8=3/4
2/5=16/40
1/8=5/40
8/10=12/15

I hope this helps.
4 0
2 years ago
I need help on this math problem.
MrMuchimi

Answer:

its A.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
1.) Evaluate the indicated function, where f(x) = x2 − 8x + 3and g(x) = 7x − 5.
noname [10]

Answer:

1) (f + g) (5) = 18, 2) (f + g) (1/2) = - 13/4, 3) (f - g) (-1) = 14, 4) (f * g) (7) = 456, 5) (f/g) (- 2) = - 3/4, 6) (g ○ f)(x) = 6 x - 23, (f ○ g)(x) = 6 x - 6, 7) (g \circ f) (x) = \frac{9}{x} - 24, (f \circ g) (x) = \frac{1}{x - 2} + 5, 8) (f ○ g)(5) = 3

Step-by-step explanation:

1) (f + g) (x) = x^{2}-8\cdot x + 3 + 7 \cdot x - 5\\(f + g) (x) = x^{2} - x - 2\\(f + g) (5) = 18

2) (f + g) (x) = x^{2} - 7 \cdot x + 4 + 6 \cdot x - 7\\(f + g) (x) = x^{2} - x - 3\\(f + g) (\frac{1}{2} ) = - \frac{13}{4}

3) (f - g) (x) = x^{2} - 3 \cdot x + 4 - 4 \cdot x + 2\\(f - g) (x) = x^{2} - 7 \cdot x + 6\\(f - g) (-1) = 14

4) (f \cdot g) (x) = (x^{2}-4\cdot x + 3) \cdot (3\cdot x - 2)\\(f \cdot g) (7) = 456

5) (f / g) (x)  = \frac{x^{2}-3\cdot x + 2}{4 \cdot x - 8} \\(f / g) (-2) = - \frac{3}{4}

6) (g \circ f) (x) = 3 \cdot (2 \cdot x - 8) + 1\\(g \circ f) (x) = 6 \cdot x - 23\\(f \circ g) (x) = 2 \cdot (3 \cdot x + 1) - 8\\(f \circ g) (x) = 6 \cdot x - 6

7) (g \circ f) (x) = 3 \cdot (\frac{3}{x} - 6) - 6\\(g \circ f) (x) = \frac{9}{x} - 24\\(f \circ g) (x) = \frac{3}{3 \cdot x - 6} + 5\\(f \circ g) (x) = \frac{1}{x - 2} + 5

8) (f \circ g) (x) = 2 \cdot (x^{2} - 5 \cdot x) + 3\\(f \circ g) (x) = 2 \cdot x ^{2} - 10 \cdot x + 3\\(f \circ g) (5) = 3

3 0
3 years ago
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