I think false but I’m not sure
Quadratic equation has a leading degrees of 2. The correct equation in vertex form is (x - 3)^2 + 5
<h3>Vertex form of a quadratic equation</h3>
Quadratic equation has a leading degrees of 2.
Given the quadratic function expressed as:
f(x) = x^2 - 6x + 14
Complete the square
x^2 - 6x + (-3)^2 - (-3)^2 + 14
(x- 3)^2 - 9 + 14
(x - 3)^2 + 5
Hence the correct equation in vertex form is (x - 3)^2 + 5
Learn more on vertex form here: brainly.com/question/525947
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2x+4y=12 ------>1
y=1/2x-3. ------->2
2 into 1
2x+4(1/2x-3)=12
2x+2x-12=12
4x-12-12=0
4x-24=0
4x=24
x=24/4
x=6 ------> 3
3 into 2
y=1/2x-3
y=1/2(6)-3
y/=0
sorry if Im wrong or my is incorrect
Answer:
A= 6 (4+3)
Step-by-step explanation:
Answer:
5/13
Step-by-step explanation:
Cos = opp/hyp
5 is opposite of angle R and 13 is the hypotenuse.