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4 years ago

15

Pls help it’s due at 9am and i need the work too

2 answers:

Monica [59]4 years ago

8 0

Answer for 1. 72

Answer for 2.536

Answer for 3.195

Oksanka [162]4 years ago

6 0

1. is 72
2. is 536
3. is 195
4. is 432
5. is 208
6. is 450
7. is 7.4
8.is 29.4
10.is 16.2

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What is the value of X in the equation 4 3/10(2 2/5x+ 5 1/2)= 1/2( -3 3/5x + 1 1/5)?

Irina18 [472]

Answer: x= -1.02 or -95/93 or -1 2/93

Step-by-step explanation:

7 0

4 years ago

A worker with a wheelbarrow filled with bricks starts at a point 50 m from the

olga55 [171]

Step-by-step explanation:

Given

Worker started from a point 50 from entrance. The worker pushes it away from the entrance at a speed of 1 m/s for 10 s that is there is no acceleration for 10 s as speed is constant.

Distance covered in this time is given by

$\Rightarrow s_1=1\times 10\\\Rightarrow s_1=10\ m$

It is stopped for 5 s and then starts moving towards entrance with a speed of 2 m/s for 20 s. Also, there is no acceleration.

distance traveled in this time

$\Rightarrow s_2=2\times 20\\\Rightarrow s_2=40\ m$

As, distance cannot shown negative. It is shown in increasing manner.

7 0

3 years ago

Find the m 1.) 40<br> 2.) 50<br> 3.) 90<br> 4.) 180

Serhud [2]

If you are asking about angle d it’s 40. The question isn’t clear

5 0

3 years ago

Can anyone help with this???

nignag [31]

Answer:

X= 13

A=104

C=26

Step-by-step explanation:

the equation is 8x+2x+50=180

10x=130

x=13

5 0

3 years ago

Given f''(x) = - 16 sin(4x) and f'(0) = - 4 and f(0) = - 2.<br><br> Findf(1) =

cestrela7 [59]

Answer:

The complete equation is $f(x) = \sin 4x -8\cdot x -2$ . $f(1) = -10.756$

Step-by-step explanation:

Let be $f''(x) = -16\cdot \sin 4x$ , we need to determine the formula of $f(x)$ by integrating twice:

$f'(x) = \int {(-16\cdot \sin 4x)} \, dx$

$f'(x) = -16\int {\sin 4x} \, dx$

We apply the following algebraic substitution in expression above:

$u = 4\cdot x$ and $du = 4\,dx$

$f'(u) = -4\int {\sin u} \, du$

$f'(u) = 4\cdot \cos u + C_{1}$

$f'(x) = 4\cdot \cos 4x + C_{1}$

We use the same approach to determine $f(x)$ :

$f(x) = \int {(4\cdot \cos 4x)} \, dx + \int {C_{1}} \, dx$

$f(u, x) = \int {\cos u} \, du + C_{1}\int \, dx$

$f(u,x) = \sin u + C_{1}\cdot x + C_{2}$

$f(x) = \sin 4x + C_{1}\cdot x + C_{2}$

If we know that $f'(0) = -4$ and $f(0) = -2$ , the integration constants are obtained below:

$4 + C_{1} = -4$

$C_{1} = -8$

$C_{2} = -2$

The complete equation is $f(x) = \sin 4x -8\cdot x -2$ . (Angles are measured in radians) Then:

$f(1) = \sin 4 - 8- 2$

$f(1) = -0.756-8-2$

$f(1) = -10.756$

4 0

4 years ago