We can use the points (2, -2) and (4, -1) to solve.
Slope formula: y2-y1/x2-x1
= -1-2/4-(-2)
= -3/6
= -1/2
Point slope form: y - y1 = m(x - x1)
y - 2 = -1/2(x + 2)
Solve for y-intercept.
-2 = -1/2(2) + b
-2 = -1 + b
-2 + 1 = -1 + 1 + b
-1 = b
Slope Intercept Form: y = mx + b
y = -1/2x - 1
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Best Regards,
Wolfyy :)
Answer:
8
Step-by-step explanation:
Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that
<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>
<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>
where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.
Then the sum is
<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>
and its magnitude is
||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)
… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))
… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))
… = √(16 + 16 cos(135° - 45°) + 4)
… = √(20 + 16 cos(90°))
… = √20 = 2√5
Answer:
AB = 30 & BD = 16
Step-by-step explanation:
Multiply all sides by two
The value of x⁴ is equal to 79.8006702
