2 years ago

Which of the following statements is true? A. sin(j)>cos(L) B. sin(L)

Mathematics

1 answer:

olga2289 [7]2 years ago

7 0

Answer:

Step by step explanation:

maybe

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The smallest bone on the body, the stirrup-shaped stapes found in the middle ear, has a typical length of less than 0.33 cm. how

4vir4ik [10]

Answer:

0.13 inches.

Step-by-step explanation:

1 inch = 2.54 cm

So 1 cm = 1/ 2.54 in

0.33 cm = 0.33/2.54 in

= 0.13 inches.

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1 year ago

A person’s body mass index (BMI) is a measure of the amount of body fat based on height, h, in inches, and weight, w, in pounds.

topjm [15]

Answer:

21.50 to the nearest hundredth.

Step-by-step explanation:

This is (704.5 * 125) / (64)^2

= 88062.5 / 4096

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2 years ago

Y+2=-3(x-2) solve for y

luda_lava [24]

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2 years ago

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What expression is equivalent to <br> 16+2*36

Oliga [24]

Answer: It looks like this expression is 16+2 times 36, so the answer is 18 times 36 also 88, they are both equivalent

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2 years ago

Find a single expression that represents the area of the outer ring of the circle if the area of the whole circle is represented

sp2606 [1]

Answer: The answer is $A_o=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

Step-by-step explanation: Given that the area of the whole circle is represented by the expression

$A_c=25x^2-12x-9.$

We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.

Now, if 'r' represents the radius of the circle, then we have

$A_c=\pi r^2\\\\\Rightarrow \dfrac{22}{7}r^2=25x^2-12x-9\\\\ \Rightarrow r^2=\dfrac{7}{22}(25x^2-12x-9)\\\\\Rightarrow r=\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

Thus, the area of the outer ring is

$A_o=2\pi r=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

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3 years ago