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melamori03 [73]
3 years ago
15

Which of the following statements is true? A. sin(j)>cos(L) B. sin(L)

Mathematics
1 answer:
olga2289 [7]3 years ago
7 0

Answer:

a

Step by step explanation:

maybe

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For the x-values 1, 2, 3, and so on, the y-values of a function form an
o-na [289]

Answer: exponential decay

Step-by-step explanation:

6 0
3 years ago
If a+b+c=0 for a,b,c then prove a²/bc+b²/ca+c²/ab=3.
Ierofanga [76]
According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in   all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3. 
</span>hence proved


5 0
3 years ago
Ill give brainliest i really need help on this
Sever21 [200]
I think the answer is

B.
8 0
2 years ago
What is the simplified expression for,
Nostrana [21]

Here are a few rules you need to know for this equation:

  • Multiplying exponents of the same base: x^m\times x^n=x^{m+n}
  • Dividing exponents of the same base: \frac{x^m}{x^n}=x^{m-n}
  • Turning a negative exponent to a positive one: x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m

So this is our algebraic expression: \frac{3^{-4}\times 2^3\times 3^2}{2^4\times 3^{-3}}

Firstly, multiply 3^-4 and 3^2: \frac{3^{-4+2}\times 2^3}{2^4\times 3^{-3}}=\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}

Next, divide:

\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}=3^{-2-(-3)}2^{3-4}=3^12^{-1}

Next, turn the negative exponent into a positive one: 3^12^{-1}= \frac{3}{2}

<u>Your final answer is 3/2, or 1.5.</u>

6 0
3 years ago
Plz help fast will mark brainliest
Semenov [28]

Answer: -270

Step-by-step explanation:

First, simplify the exponent

-6*(25+20)

Then, distribute

-150+-120

Then, subtract(add a negative)

-270

Hope it helps <3 :)

6 0
3 years ago
Read 2 more answers
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