I tried but see if this helps you In algebra, it is easy to find the third value when two values are given. Generally, the algebraic expression should be any one of the forms such as addition, subtraction, multiplication and division. To find the value of x, bring the variable to the left side and bring all the remaining values to the right side.
First you must add/subtract all like terms. For example, 2y4 and 6y4 can be simplified. Once you have all your variables combined, you will get your answer.
I'll offer you a deal in return for your 5 points: I'll solve it . . . . You check it.
<u>-1/2x - 7 = -11</u>
Add 7 to each side: -1/2 x = -4
Multiply each side by 2 : - x = -8
Multiply each side by -1 : <em> x = 8</em>
Take it Allalala !
I wasn't going to click on this entry, but the ALL-CAPS entranced me and enthralled me, so I had to click it.
well, if he gave his dog 1/5 of the money, what's left is just 4/5, recall 5/5 is a whole, so
![\bf \cfrac{4}{5}+\cfrac{1}{5}\implies \cfrac{5}{5}\implies 1whole](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B4%7D%7B5%7D%2B%5Ccfrac%7B1%7D%7B5%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B5%7D%5Cimplies%201whole)
now, let's divide that 4/5 in 3 even pieces
![\bf \cfrac{\frac{4}{5}}{3}\implies \cfrac{\frac{4}{5}}{\frac{3}{1}}\implies \cfrac{4}{5}\cdot \cfrac{1}{3}\implies \cfrac{4\cdot 1}{5\cdot 3}\implies \cfrac{4}{15}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B%5Cfrac%7B4%7D%7B5%7D%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B%5Cfrac%7B4%7D%7B5%7D%7D%7B%5Cfrac%7B3%7D%7B1%7D%7D%5Cimplies%20%5Ccfrac%7B4%7D%7B5%7D%5Ccdot%20%5Ccfrac%7B1%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B4%5Ccdot%201%7D%7B5%5Ccdot%203%7D%5Cimplies%20%5Ccfrac%7B4%7D%7B15%7D)
now, his donation to each charity was 60 bucks, so 4/5, of say "x", "x" being to total amount, is 60, thus (4/5)x = 60
![\bf \cfrac{4}{5}x=60\implies \cfrac{4x}{5}=60\implies x=\cfrac{5\cdot 60}{4}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B4%7D%7B5%7Dx%3D60%5Cimplies%20%5Ccfrac%7B4x%7D%7B5%7D%3D60%5Cimplies%20x%3D%5Ccfrac%7B5%5Ccdot%2060%7D%7B4%7D)
and surely you know how much that is.
Answer:The given system of equations has no solution
Explanation:The first given equation is:
2y + 5x = 10
This can be rewritten as:
2y = 10 - 5x ...............> equation I
The second given equation is:
4y + 10x = 2
This can be rewritten as:
2(2y) + 10x = 2 ................> equation II
Substitute with I in II and solve as follows:
2(2y) + 10x = 2
2(10-5x) + 10x = 2
20 - 10x + 10x = 2
20 = 2
Since this is impossible, therefore, the system of equations has no solutions. This means that there is no (x,y) point that would satisfy both equations.
Graphing check:The attached image shows the graphs of the two given functions. We can note that the two lines are parallel each with slope -5/2, which means that they NEVER intersect.
Hence, there is no solution for the given system.
Hope this helps :)