It would be 60 because all you do is double the radius because it is only half of the circle
It would be D)
Hope this helps
x = 10.22 in
Solution:
Width of the figure = x in
Length of the figure = (2x + 5) in
Area of the figure = 260 in²
<u>To find the value of x:</u>
<em>Area of the figure = length × width</em>
length × width = 260
(2x + 5) × x = 260
Subtract 260 from both sides of the equation.
Factor the above quadratic expression.
Quadratic equation formula:
x = 10.22, x = –12.72006
Dimension of the figure cannot be measured in negative terms.
Hence x = 10.22 in.
( 2a + 3 ) - ( 4a - 8 ) = 7
2a + 3 - 4a + 8 = 7
-2a + 11 = 7
-2a = -4
a = -4 / -2
a = 2
Answer:
The sample space is:
- (T,N): table height and brown
- (T, W): table height and white
- (T, K) : table height and black
- (B, N): bar height and brown
- (B, W): bar height and white
- (B, K): bar height and black
- (X, N): XL height and brown
- (X, W): XL height and white
- (W, K): XL height and black
Explanation:
The <em>sample space </em>is the set of all the possible outputs, i.e. the possible different combinations that can be choosen.
Use the letters T, B, and X to represent, respectively, table height, bar height, and XL height,
Use letters N, W, and K to represent, respectively, the colors brown, white and black.
Each combination consists of a height (T, B or X) and a color (N, W, K); thus, your sample space shall have 3 × 3 different combinations. These are:
- (T,N): table height and brown
- (T, W): table height and white
- (T, K) : table height and black
- (B, N): bar height and brown
- (B, W): bar height and white
- (B, K): bar height and black
- (X, N): XL height and brown
- (X, W): XL height and white
- (W, K): XL height and black
