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2 years ago

PLEASE HELP ME! asap please

Mathematics

2 answers:

iren2701 [21]2 years ago

4 0

The answer is the second option I took the test

Radda [10]2 years ago

3 0

Answer:

Step-by-step explanation:

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The charge is $12 plus $0.15 per tree. What is the greatest number of trees that can be planted if you spend no more than $70

notsponge [240]

Answer:

386

Step-by-step explanation:

If you subtract the initial fee of 12 from 70 you get 68 you just divide that by .15 meaning you can plant no more that 386 trees.

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2 years ago

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Paladinen [302]

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2 years ago

Find all solutions of the given system of equations and check your answer graphically. hint [see examples 1-4.] (if there is no

zlopas [31]

x − y = 0 = difference

x + y = 4 = sum

Can be solved by the sum and difference rule (most of the time without pen and paper)

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3 years ago

3x2/15 simplest from

Soloha48 [4]

Answer:

0.4 or 6/15

3×2 is 6

leaving 6/15 or 0.4

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8 months ago

30 points!!<br> What is the sum of the first six terms of the series?<br> 48 - 12 + 3 - 0.75 +...

Lunna [17]

Answer:

The sum of the first six terms is 38.39

Step-by-step explanation:

This is a geometric sequence since the common difference between each term is $-\frac{1}{4}$

Thus, $r=-\frac{1}{4}$

To find the sum of first six terms, we need to find the fifth and sixth term of the sequence.

To find the fifth term:

The general form of geometric sequence is $a_{n}=a_{1} \cdot r^{n-1}$

To find the fifth term, substitute $n=5$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{5} &=(48) \cdot\left(-\frac{1}{4}\right)^{5-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{4} \\&=(48)\left(\frac{1}{256}\right) \\a_{5} &=0.1875\end{aligned}$

To find the sixth term, substitute $n=6$ in $a_{n}=a_{1} \cdot r^{n-1}$

$\begin{aligned}a_{6} &=(48) \cdot\left(-\frac{1}{4}\right)^{6-1} \\&=(48) \cdot\left(-\frac{1}{4}\right)^{5} \\&=(48)\left(-\frac{1}{1024}\right) \\a_{5} &=-0.046875\end{aligned}$

To find the sum of the first six terms:

The general formula to find Sn for $|r|$ is $S_{n}=\frac{a\left(1-r^{n}\right)}{1-r}$

$\begin{aligned}S_{6} &=\frac{48\left(1-\left(-\frac{1}{4}\right)^{6}\right)}{1-\left(-\frac{1}{4}\right)} \\&=\frac{48\left(1-\frac{1}{4096}\right)}{1+\frac{1}{4096}} \\&=\frac{48(0.95)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{48(0.9998)}{5} \\&=\frac{47.9904}{5} \\&=38.39\end{aligned}$

Thus, the sum of first six terms is 38.39

5 0

2 years ago