(3³ x 5³)² - 2
( 27 x 125)² - 2
125 x 27 = 3375
3375² = 11,390,625
11,390,625 - 2 = 11,390,623
See attached files for detailed solutions
To answer your question, the answer would be 8
Answer:
0.82
Step-by-step explanation:
The question says that three percent (3 out of 100) of the rackets (racquets) produced by the company are found to be defective.
First thing to calculate is the probability that 1 in a box of 6 rackets are defective.
That probability is gotten by cross multiplying, as illustrated below;
3 - 100
x - 6
x = (6×3)/100 = 18/100 = 0.18
Since the probability of having/finding 1 defective racket in a box of 6 is 0.18, the probability of finding more than 1 (minimum of 2 and maximum of all six) defective rackets in same box would be (1 - 0.18) = 0.82
Answer:
i am way
Step-by-step explanation:
to youn for thi
