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SSSSS [86.1K]
4 years ago
5

Find the zeros of the function f(x) = x2+ 6x + 18. The 2 is square

Mathematics
1 answer:
Novay_Z [31]4 years ago
6 0
To find the number of zeros in the quadratic equation we factorize it as follows:
f(x)=x²+6x+18
solving using completing square methods we obtain:
x^2+6x=-18
c=(b/2a)^2=9
thus
x²+6x+9=-18+8
x²+6x+9=-9
(x+3)²=-9
hence
x=-3+/-3i
the roots are:
x=-3+3i or x=-3-3i
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Answer:

4

Step-by-step explanation:

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4 0
3 years ago
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4 years ago
11 = -d + 15<br> PLEASE ANSWER FAST
Oksanka [162]

Answer:

<h2>d=4</h2>

Step-by-step explanation:

Let's solve your equation step-by-step.

11=−d+15

Step 1: Flip the equation.

−d+15=11

Step 2: Subtract 15 from both sides.

−d+15−15=11−15

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Step 3: Divide both sides by -1.

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4 0
3 years ago
Read 2 more answers
What will the answer be?
Readme [11.4K]
To simplify: 

Subtract  3 from 8 = 5
Reduce 2/4 = 1 / 2

And the answer is:
1 /2 d^5

8 0
4 years ago
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