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Alinara [238K]
3 years ago
8

Light travels at approximately 2.998*10^5 kilometers per second. There are 6.048*10^5 seconds in one week. About how many kilome

ters does light travel in one week. Which operation are we using?
Mathematics
1 answer:
BartSMP [9]3 years ago
6 0

Answer:

okay, you have pay special attention to time.i.e 60secs = 1 minute, 60 minutes = 1 hour, 24 hours in one day, and 7 days in one week. No. of seconds in one week we are told is 6.1048 x 10 ^5 seconds.  

Step-by-step explanation:

s = d/t [ speed = distance/time]

therefor, rearranging, we get d = s x t

Since speed = 2.998*10^5 Km/s and time = 6.048^10^5

d = (2.998 x 10^5) x (6.048 x10^5) = (2.998 x 6.048) x 10 ^(5+5)

d = 18.131904 X 10^10 km

d = approximately 18.132 x 10^10 km (to 3 decimal places)

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Ons: Practice
Sedaia [141]

Answer:

x = 18

Step-by-step explanation:

Given

\frac{x}{6} - 7 = -4

Required

Solve for x

\frac{x}{6} - 7 = -4

Add 7 to both sides

\frac{x}{6} - 7+7 = -4+7

\frac{x}{6}  = -4+7

\frac{x}{6}  = 3

Multiply through by 6

6 * \frac{x}{6}  = 3 * 6

x = 3 * 6

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7 0
3 years ago
$4 for <br> 1<br> 4<br> of a pie. What is the cost of a whole pie?
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Answer:

$16

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4 0
3 years ago
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I need answer for this question
just olya [345]

The probability that the aircraft is overloaded is 97.98%, which means the pilot should take the action.

In a Normal distribution with mean ц and standard deviation σ, the z-score of a measure x is given by:

Z = X-ц / σ

· It measures how many standard deviations the measure is from the mean.

· After finding Z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

· By the Central Limit Theorem, the sampling distribution of sample means of the size n has standard deviation σ

σ = σ / \sqrt{n}    

σ is standard deviation

n is the sample size.

Given that the mean and the standard deviation of the population is 176.1 lb and 35.4 respectively.

⇒ ц = 176.1  and σ = 35.4

For a sample of 43 passengers, we have

n = 43

σ =  \frac{35.4}{\sqrt{43}}

σ = 5.398

Z = X-ц / σ

Z = \frac{165-176.1}{5.398}

Z = -2.05 has p- value of 0.9798

The probability that the aircraft is loaded is

1 - p-value of Z

1 - 0.0202 = 0.9798

The probability that the aircraft is overloaded is 97.98%

Know more about Normal probability Distribution: -brainly.com/question/9333901

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1 year ago
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Is he measured how much gallons was in the pool in the first minute he can times that amount by 11 minutes and ended up with 55 gallons
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