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SCORPION-xisa [38]
3 years ago
14

Which pair is made up of prime numbers 11 & 33 , 42 & 56 , 37 & 67, 57 & 97

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0

Answer:

37 & 67

Step-by-step explanation:

11 & 33

  • 11 - 1, 11
  • 11 is prime
  • 33 - 1, 3, 11, 33
  • 33 is composite number
  • 11 & 33 is incorrect

42 & 56

  • 42 - 1, 2, 3, 6, 7, 14, 21, 42
  • 56 - 1, 2, 4, 7, 8, 14, 28, 56
  • Both 42 and 56 are composite numbers
  • 42 & 56 is incorrect

37 & 67

  • 37 - 1, 37
  • 67 - 1, 67
  • Both 37 and 67 are prime numbers
  • 37 & 56 is correct

57 & 97

  • 57 - 1, 3, 19, 57
  • 97 - 1, 97
  • 57 is a composite number, 97 is a prime number
  • 57 & 97 is incorrect
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Answer:

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Step-by-step explanation:

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Since the first number corresponds with zero, that means our y intercept is the first number.

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Help me pleasee<br> Questions r in picture
jok3333 [9.3K]
<h2>Answer:</h2>

\large \bf\implies\frac{12}{61}

<h2>Step-by-step explanation:</h2>

<h2>Given :</h2>

\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...

<h2>To Find :</h2>

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<h2>Solution :</h2>

We have to add 1 in numerator and -10 in denominator because

\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...[Given]

\frac{8  \: + \:  1}{101 \:  - \:  10}  =  \frac{9}{91} \\\\  \frac{9 + 1}{91 - 10}  =  \frac{10}{81}  \\ \\ \frac{10 + 1}{81 - 10}  =  \frac{11}{71}  \\ \\ \frac{11 + 1}{71 - 10}  =  \frac{12}{61} ...

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