Centimeters are the metric unit of length
Answer:
a) 91 1/6 gallons
b) 2502 miles
Step-by-step explanation:
You are given a number of miles and a number of gallons for the car. The ratio of these numbers is ...
(261 mi)/(14.5 gal) = 18 mi/gal
We presume this value is constant for this car. Then the questions can be answered by forming and solving a proportion:
a) 1641 miles/(gallons) = 18 mi/(1 gal)
Multiplying by gallons and dividing by 18 mi/gal, we get
1641/18 gal = (gallons) = 91 1/6 gal
It will take 91 1/6 gallons of gasoline for Mary to drive to her friend's house.
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b) Same deal, but the miles are unknown.
(miles)/(139 gal) = (18 mi)/(1 gal)
Multiplying by 139 gal gives ...
(18 mi)·139 = (miles) = 2502 mi
139 gallons of gasoline will let Mary drive 2502 miles.
$15 x .0725 = 1.0875 which we have to round to $1.09
Notice how I changed the 7.25% to a decimal .0725 by moving it back two places.
Answer:
Leg1 = 9 and leg2 = 12
Step-by-step explanation:
<u>Points to remember</u>
<u>Pythagorean theorem</u>
Hypotenuse² = Base² + Height²
<u>To find the length of each leg</u>
It is given that, hypotenuse = 15 feet
Let base = x the height = x +3
By using Pythagorean theorem we can write,
Hypotenuse² = Base² + Height²
15² = x² + (x + 3)²
225 = x² + x² + 6x + 9
2x² + 6x + 216 = 0
x² + 3x + 108 = 0
By solving we get x = 9 and x -12
Therefore one leg = 9 and other leg = 9 + 3 = 12