The answer to this question is E.
There are 720 total different combinations, and 24 of those will have the letters DAY consecutively within all those combinations.
<u>Explanation:</u>
FRIDAY is a six letter word.
To form all combinations of letters, we would have six choices of letters to fill the first spot. Whatever letter you choose for the first spot, you then have five choices of letters to fill the second spot. Four choices of letters to fill the third spot. And so on.
So, the total number of different combinations of the six letters would be 6!
6! = 6 X 5 X 4 X 3 X 2 X 1
= 720
DAY could appear consecutively starting in 4 different spots: the 1st, 2nd, 3rd, and 4th spots of all combinations. DAY will appear consecutively 6 times in each of those 4 starting spots.
6 X 4 = 24.
So, there are 720 total different combinations, and 24 of those will have the letters DAY consecutively within all those combinations.
Answer:
c. 10
Step-by-step explanation:
Eliminate parentheses using the distributive property.
3(b+4) -2(2b+3) = -4 . . . . given
3b +12 -4b -6 = -4 . . . . . parentheses eliminated
-b +6 = -4 . . . . . . . . . . . . collect terms
-b = -10 . . . . . . . . . . . . . . subtract 6
b = 10 . . . . . . . . . . . . . . . . multiply by -1
_____
The rules of equality require that any operation you perform on one side of the equal sign must also be done on the other side. So when we say "subtract 6", we assume you know that means "subtract 6 from both sides of the equation", for example.
3 × 100 = 300
the easiest way to do it is just add the same amount of zero's to the number you multiplied with. for example
3 × 10000 if you would just take out the zero's
it would look like this. 3 × 1
the answer of course would be 3 then you can put the zero's back in the answer (30000)
at least that's how I understood it
3 × 100 =
3 × 1(00) =
-->
-->
(00)
3 × 1(00) = 3
3 × 100 = 300
80.8, 40.4, 20.2, 10.1 (the numbers are going in half.)
1024, 512, 256, 128. (also going in half.)
