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wariber [46]
3 years ago
10

HELP THESE ARE REALLY TRICKY BUT FUN PROBLEMS PLUS I WILL GIVE BRAINLIEST!

Mathematics
1 answer:
Virty [35]3 years ago
4 0

Answer:

1. r = 7√2 dm ≈ 9.90 dm

2. ∠ENK = 50°; ∠KEG = 59°

Step-by-step explanation:

1. If ∠A is 90°, then the angle at O that is opposite is also 90°, hence the tangent lines and radii make a square. The diagonal of the square (OA) is 14 dm, so the side length, the radius, will be 14/√2 dm = 7√2 dm.

__

2. The length of chord EK is the same as the length of chord VG, so arc EK is the same measure as arc GV, namely 50°. The measure of ∠ENK is the average of the measures of arcs EK and GV, so is also 50°.

∠EGK = 25°, since it is half the measure of arc EK. The sum of the angles in ΔKEG is 180°, so we have ...

∠EKG + ∠EGK + ∠KEG = 180°

∠KEG = 180° - 96° -25° = 59°

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Lila evaluates the expression using the following steps:(−7.13+63.97)+(−54.8−3.4)−71.1+(−58.2)−129.3Describe the error that Lila
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8 0
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Read 2 more answers
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Step-by-step explanation:

We assume that x should represent the number of units of plants

Also y to represent the number of animals.

So, minimze (z) = 30 x + 15 y

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10  x + 25 y ≥ 300

               y  ≤ 8

 0  ≤  x  ≤ 25

 0  ≤  y  ≤ 25

Changing the above linear inequalities into linear equation; we have:

30 x + 20 y =  360  

10  x + 25 y = 300

               y  = 8

The graph for the above discussion can be located in the attached diagrammatic expression below:

NOW, the corner points (0,18),(0,25),(25,25), and (25,8) can be calculated from the graph. From the diagram, the corner point  [\frac{60}{11} , \frac{108}{11} ] can be found by solving the system.

30 x + 20 y =  360  

10  x + 25 y = 300

Corner point (10, 8) = 10 x + 25 y = 300

                                                   y  = 8

Corner point                               Value of z = 30 x + 15 y

(0,18)                                            270

(0,25)                                           375

(25,25)                                         1125

(25,8)                                            870

[\frac{60}{11} , \frac{108}{11} ]                                          \frac{3420}{11} ≅ 310.91

(10, 8)                                            420

∴

The minimum  labor = 270 hours and it is obtained when 0 units of plants and 18 animals are collected.

8 0
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