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rodikova [14]
3 years ago
5

7.50 on 250.00 is what percentage

Mathematics
1 answer:
natita [175]3 years ago
5 0

Answer:

the answer is 3 zz

Step-by-step explanation:

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Divide 72 ft in the ratio 9:4:5
Anton [14]
9:4:5.....added together = 18

9/18 (72) = 648/18 = 36
4/18 (72) = 288/18 = 16
5/18 (72) = 360/18 = 20

so we have 36:16:20
5 0
4 years ago
7/8m + 9/10 - 2m - 3/5
castortr0y [4]
-9/8m+3/10. There is a nice algebra calculator that i use called mathpapa.com
Heres the link.
7 0
4 years ago
Read 2 more answers
Is this correct???? TYSM
vfiekz [6]

Yep, this is all correct!

-6/2 = y/4

y = (-6×4)/2

y = -24/2

y = -12


x was multiplied by 2

and y was also multiplied by 2

5 0
4 years ago
RSM QUESTION NEED HELP!!!!!! A biker traveling at his usual speed can go from his house to work in 4 hours. When the weather is
kogti [31]
<h3>Answer:   216 miles</h3>

=======================================

Work Shown:

d = distance from work to his house

x = speed when weather is good

y = speed when weather is bad

y = x-6 since he travels 6 mph slower

------------------------

On a good weather day, he travels for 4 hours and goes at x mph

distance = rate*time

d = r*t

d = x*4

d = 4x

----------------------

On a bad weather day, he travels 4.5 hours (half hour more than 4 hrs) and goes at y = x-6 mph

d = r*t

d = y*4.5

d = 4.5y

d = 4.5(x-6) .... replace y with x-6

d = 4.5x-27 .... distribute

----------------------

The values of d for both equations are the same, as the biker is traveling the same distance. So we can equate the two right hand sides (RHS) and solve for x.

4.5x-27 = 4x

4.5x-4x = 27

0.5x = 27

x = 27/0.5

x = 54

The biker's speed on a good weather day is 54 mph.

A bad weather day's speed would be y = x-6 = 54 - 6 = 48 mph.

----------------------

Now compute the value of d

d = 4x

d = 4*54

d = 216

The biker travels 216 miles on a good weather day

or,

d = 4.5*y

d = 4.5*48

d = 216

the biker travels that same distance on a bad weather day.

3 0
4 years ago
Which plane is parallel to plane CIJ??
tekilochka [14]

Answer:

Step-by-step explanation:

??

5 0
3 years ago
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