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Alchen [17]
3 years ago
13

A rocket is launched at 85 ft./s from a launch pad that’s 28 feet above the ground. which equation can be used to determine the

height of the rocket at a given time after the launch? (answer choices in picture)

Mathematics
2 answers:
Fed [463]3 years ago
5 0

Answer:

The correct option is the last option

h(t) = 28 + 85t -16t ^ 2

Step-by-step explanation:

The kinematic equation to calculate the position of a body on the vertical axis as a function of time is:

h(t) = h_o + v_ot - \frac{1}{2}gt ^ 2

Where:

h_0 = initial position = 28ft

v_0 = initial velocity = 85 ft / s

g = acceleration of gravity = 32.16ft / s ^ 2

Then the equation sought is:

h(t) = 28 + 85t - \frac{1}{2}32.16t ^ 2

Finally:

h(t) = 28 + 85t -16t ^ 2

The correct option is the last option

Arlecino [84]3 years ago
3 0

Answer:

h(t)=-16t^2+85t+28 is equation of height of rocket at given time after the launch.

D is correct.

Step-by-step explanation:

A rocket is launched at 85 ft./s from a launch pad that’s 28 feet above the ground

We have an equation of rocket launching.

h(t)=\dfrac{1}2gt^2+v_ot+h_o

Where, g is acceleration due to gravity

v is initial velocity

h is initial height

h(t) is function of height at any time t

A rocket is launched by 85 ft/s

V_o=85\ ft/s

g=-32\ ft/s

h_o=28

Substitute the value into formula ans get formula

h(t)=-16t^2+85t+28

Hence, D is correct. Equation of height of rocket at given time after the launch.

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