What is the value of the expression (9 1/3)^3?

Mathematics

1 answer:

cestrela7 [59]3 years ago

5 0

Answer:

rounded to the nearest hundredth the value is 813.04

Step-by-step explanation:

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Please help I need it done right now

Lina20 [59]

Use the way that kids use i.e trial and error method .

Solution:-

The set given by

$\\ \rm\longmapsto \left\{32+n,\dfrac{n}{8},\sqrt{n+225}\right\}$

Lets understand

See the first term any natural value will make it natural .

Come to 2nd one.

n should be a multiple of 8 to make it whole.

Come to third one

n should be a number which makes the sum a perfect square by which we get a natural no.We have to solve it w.r.t to 2nd one

Lets think

Nearest squares to 225 are 196 and 289

We can't take 196 as we have to take a positive one other wise it will come in terms of i.

Take 289

$\\ \rm\longmapsto n+225=289$

$\\ \rm\longmapsto n=289-225=64$

Its divisible by 8 .

Rewrite the set

$\\ \rm\longmapsto \left\{64+32,\dfrac{64}{8},\sqrt{225+64}\right\}$

$\\ \rm\longmapsto \left\{96,8,\sqrt{289}\right\}$

$\\ \rm\longmapsto \left\{96,8,17\right\}$

Hence n=64

8 0

3 years ago

You have a ruler of length 2 and you choose a place to break it using a uniform probability distribution. Let random variable X

Dmitriy789 [7]

Hi!

When you break the rule for the first time, de probability distribution of X is constant in [0, 2], and is zero outside. If the the value obtained is X = a, then the probability distribution of Y (conditioned on X = a) is constaint in interval [0, a], and zero outside. Then the region in the X-Y plane where the joint density is non-zero is the filled triangle in the figure.