Factor to find the zeros of the function defined by the quadratic expression. −13x2 − 130x − 273

Mathematics

1 answer:

rewona [7]3 years ago

7 0

Answer The Zeros are x= -3,-7

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The price of a refrigerator is advertised at a special price of R2199. The original price was R2499. What percentage discount wa

k0ka [10]

Answer:

12.01% discount

Step-by-step explanation:

R2499-100%

R2199-?

=R2199/R2499×100%

=87.99

100%-87.99%=12.01%

6 0

3 years ago

Order from least to greatest: ‐7, 9, 0, 33, ‐56, 78, ‐1

Leona [35]

Answer:

-56, -7, -1, 0, 9, 33, 78

6 0

3 years ago

A standard deck of cards contains 52 cards. One card is selected from the deck.(a)Compute the probability of randomly selecting

Aneli [31]

a. There are four 5s that can be drawn, and $\binom43=4$ ways of drawing any three of them. There are $\binom{52}3=22,100$ ways of drawing any three cards from the deck. So the probability of drawing three 5s is

$\dfrac{\binom43}{\binom{52}3}=\dfrac4{22,100}=\dfrac1{5525}\approx0.00018$

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of $\frac8{52}=\frac2{13}\approx0.15$ of getting drawn.

b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability $\frac{12}{52}=\frac3{13}\approx0.23$ of being drawn.

c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of $\frac{16}{52}=\frac4{13}\approx0.31$ .