Use the hypergeometric distribution.
M=number of Men=5
F=number of women=4
m=number of men elected=2
f=number ow women elected=2.
Assuming equal chance to get elected, then
P(2M,2F)=C(M,m)*C(F,f)/C(M+F,m+f)
=C(5,2)*C(4,2)/C(9,4)
=10*6/126
=10/21
Reference: Hypergeometric distribution.
(4.8*10^8)/(1.2*10^4)2.2*10^-8=11/<span>12500</span>
I hope this helps
Answer:
yep this kinda hard!!!!!!!!!!!!?!??!
Answer:
B
Step-by-step explanation:
B is the correct answer.
Answer:
m∠6 = 116°
Step-by-step explanation:
<u>first find x:</u>
7x - 17 = 2x + 78
subtract 2x from both sides: 5x - 17 = 78
add 17 to both sides: 5x = 95
divide by 5: x = 19
<u>plug x into 7x - 17</u>
7(19) - 17 = 116
∠6 and 7x - 17 are vertical angles and therefore congruent, so m∠6 also = 116°
