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Pie
3 years ago
9

Charles uses a graphing calculator to find a quadratic regression model f for a given set of data. When he compares model f to a

n earlier regression model g for the same data, he determines that g more accurately models the data. Which of the following statements are true? Select all that apply.
A. Function f likely had fewer residuals near the x-axis than function g.
B. Function f likely had more residuals equal to 0 than function g.
C. Function g had more residuals near the y-axis than function f.
Mathematics
1 answer:
makvit [3.9K]3 years ago
7 0
B I hope this helped I’m not sure
You might be interested in
Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab
Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx

If f(x)=x^2, then

f'(x)=2x

and

b=0\\ \\a=2

Therefore,

SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx

Apply substitution

x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du

Then

SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du

Now

\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))

Hence,

SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}

3 0
3 years ago
I need help i'm really stuck
Ivenika [448]

Answer:

8

Step-by-step explanation:

If the area is 32 and the formula for area of a triangle is base * height / 2, and you have base = 8 and height = x and area = 32, this would be:

8 * x / 2 = 32

Now, solve:

8x/2=32\\4x=32\\x=8

4 0
3 years ago
Read 2 more answers
You are installing a new pre-constructed fence in front of your house. each fence section measures 4 ½ feet wide, and each end w
irga5000 [103]
Since, each side of the fence should have the 1 3/4 feet wide decorative piece, the width of the fence should be subtracted by 2 pieces (1 3/4 feet)
                                 = 26.5 feet
Then, divide the remaining width by 4.5 feet and the answer is 5.88. Thus, approximately 5 pieces of the 4 1/2 feet should be installed. 
4 0
3 years ago
Read 2 more answers
A certain builder is selling five homes for the following prices: $157,000, $168,000, $195,000, $235,000, and $256,000. If the p
N76 [4]
Answer: $266,000

Explanation: $256,000 + $10,000 = $266,000
6 0
3 years ago
Simplify 17^2 and 18.79^2.
Westkost [7]

17^2 is 289

18.79^2 is 353.0641

7 0
3 years ago
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