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DENIUS [597]
3 years ago
5

Greg has 25 tokens for the subway. He uses three tokens each week. How many weeks can he use the subway before he has to buy mor

e tokens?
Mathematics
1 answer:
Fudgin [204]3 years ago
7 0

Answer:

8 1/3 weeks

Step-by-step explanation:

25/3 = 8 1/3

so he can ride the subway for 8 1/3 weeks

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The angle \theta_1θ 1 ​ theta, start subscript, 1, end subscript is located in Quadrant \text{II}IIstart text, I, I, end text, a
andrew11 [14]

Answer:

\cos(\theta_1)=-\dfrac{\sqrt{15}}{4}

Step-by-step explanation:

The angle \theta_1 is located in Quadrant II.

\sin(\theta_1)=\dfrac{1}{4}

From trigonometry, we know that:

\sin(\theta)=\dfrac{Opposite}{Hypotenuse}\\$Therefore:\\Opposite=1\\Hypotenuse=4\\Using Pythagorean theorem:\\Hypotenuse^2=Opposite^2+Adjacent^2\\4^2=1^2+Adjacent^2\\Adjacent^2=16-1\\Adjacent^2=15\\Adjacent=\sqrt{15}

Now, in Quadrant II,

  • The x-axis is negative
  • The y-axis is positive

Therefore, the Adjacent angle to \theta_1 =-\sqrt{15}

Therefore:

\cos(\theta_1)=\dfrac{Adjacent}{Hypotenuse}=\dfrac{-\sqrt{15}}{4}\\\\\cos(\theta_1)=-\dfrac{\sqrt{15}}{4}

8 0
3 years ago
A line segment is graphed on a coordinate plane with a length of 10 units and an endpoint located at (-2,-3). What could be the
Roman55 [17]

I think A. not so sure though sorry if I'm wrong

8 0
3 years ago
A rectangular painting with a length of 54 cm has an area of 2052 cm² what is the width of the painting
garri49 [273]

\huge \bold{ \mathfrak{ \red{Question} }}

A rectangular painting with a length of 54 cm has an area of 2052 cm² what is the width of the painting .

\huge {\bold {\mathfrak \red{Solution}}}

\mathsf{length = 54cm} \\    \mathsf{area = 2052} \\   \mathsf{breadth = x} \\ area = 2052 \\ l \times b = 2052 \\ 54 \times x = 2052 \\ x =  \frac{2052}{54}  \\  \boxed{x = 38cm}

3 0
3 years ago
3a+6b-a-9b please help!
faust18 [17]
Answer: 2a - 3b
You can try rearranging it , it’ll be easier I think :)
3a + 6b - a - 9b
= 3a - a + 6b - 9b
= 2a - 3b
6 0
3 years ago
In the summer of 2014, the average listing price for homes for sale in the Hollywood Hills was $2,663,995.
Wewaii [24]

Answer:

  • monthly payment: $15,903.61
  • interest: $2,368,664.10

Step-by-step explanation:

a) The loan amount is 90% of the price shown, so is ...

  0.90 × $2,663,995 = $2,397,595.50

The monthly loan payment is given by the amortization formula:

  A = P(r/12)/(1 -(1 +r/12)^(-12t))

  A = $2,397,595.50(0.0525/12)/(1 -(1 +0.0525/12)^(-12·30))

  A = $13,239.61

The monthly escrow payment will be 1/12 of the annual amount:

  0.012 × $2,663,995 / 12 = $2664.00

So, the total monthly payment on the house will be ...

  $13,239.61 +2664.00 = $15,903.61

__

b) The sum of monthly loan payments is ...

  $13,239.61 × 360 = $4,766,259.60

so the interest on the $2,397,595.50 loan is ...

  $4,766,259.60 -2,397,595.50 = $2,368,664.10

7 0
4 years ago
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