Answer:
7/25
Step-by-step explanation:
Let 
so we have 
As 
, we'll have ![\cos[2\arcsin(\frac{3}{5})]=\bigr[\cos(\arcsin(\frac{3}{5}))\bigr]^2-\bigr[(\sin(\arcsin(\frac{3}{5}))\bigr]^2](https://tex.z-dn.net/?f=%5Ccos%5B2%5Carcsin%28%5Cfrac%7B3%7D%7B5%7D%29%5D%3D%5Cbigr%5B%5Ccos%28%5Carcsin%28%5Cfrac%7B3%7D%7B5%7D%29%29%5Cbigr%5D%5E2-%5Cbigr%5B%28%5Csin%28%5Carcsin%28%5Cfrac%7B3%7D%7B5%7D%29%29%5Cbigr%5D%5E2)
To determine 
, construct a right triangle with an opposite side of 3 and a hypotenuse of 5. This is because since 
, then 
. If you recognize the Pythagorean Triple 3-4-5, you can figure out that the adjacent side is 4, and thus, 
. This means that 
.
Hence, ![\cos[2\arcsin(\frac{3}{5})]=(\frac{4}{5})^2-(\frac{3}{5})^2=\frac{16}{25}-\frac{9}{25}=\frac{7}{25}](https://tex.z-dn.net/?f=%5Ccos%5B2%5Carcsin%28%5Cfrac%7B3%7D%7B5%7D%29%5D%3D%28%5Cfrac%7B4%7D%7B5%7D%29%5E2-%28%5Cfrac%7B3%7D%7B5%7D%29%5E2%3D%5Cfrac%7B16%7D%7B25%7D-%5Cfrac%7B9%7D%7B25%7D%3D%5Cfrac%7B7%7D%7B25%7D)
Answer:
B. the mean of city A is greater than the mean of city B
Step-by-step explanation:
Find mean by adding every number than dividing by the total of numbers added so...
97+98+96+98+99=488 and 488/5=97.6 which is higher than the mean of city B
<span>y=(4/9)x-2
This is in slope intercept form (y=mx+b), where m is the slope.
A perpendicular line will have the opposite reciprocal of the slope.
So if the slope here is 4/9, then the perpendicular line's slope will be -9/4.
Now that you have the slope (-9/4) and a point (4, 3), you can use the point-slope formula to find the equation.
y - y</span>₁ = m(x - x₁)
y - 3 = (-9/4)(x - 4)
y - 3 = (-9/4)x + 9
y = (-9/4)x + 12
So the answer will be:
C. <span>y= -(9/4)x+12</span>
Answer:
can you insert a picture or other information to answer this pls
Step-by-step explanation:
Cd can interlock with the quadrilateral
