Question

Find the distance between P1(1, -91°) and P2(3, 335°) on the polar plane.

Answer 1

Answer:

2.749

Step-by-step explanation:

Use the polar distance formula:

$\sqrt{r_{1}^{2}+{r_{2}^{2}-2 r_{1} r_{2}cos(theta_{1} -theta_{2})$

$\sqrt{10^{2}+{3^{2}-2(1) (3)cos(225-(-91))$

2.749