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Vladimir [108]
3 years ago
5

0.00237 in scientific notation

Mathematics
1 answer:
vladimir1956 [14]3 years ago
6 0
The answer is 2.37 × 10^-3
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Helppppp mathhhhhhhhhhhh
antoniya [11.8K]
The first one is the correct answer, enjoy!
3 0
2 years ago
I need help finding the slope with work tho please
Hatshy [7]

Answer:

first is 2/5

second is -2

7 0
2 years ago
the area of a rectangular field 4641 m squared. If the width of the field is 51 m, what is its length?
shusha [124]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ The length of the field is 91 m.

Divide to find the missing length:

4641 ÷ 51 = 91

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

5 0
3 years ago
Read 2 more answers
A certain brand of jelly beans are made so that each package contains about the same number of beans. The filling procedure is n
pantera1 [17]

Answer:

p=0.063

Step-by-step explanation:

Let X be number of the certain brand of jelly beans that are made so that each package contains about the same number of beans.

X is N(375, 8)

YOu are collecting a sample size of

n = 8

Findings from the sample

\bar x =370\\

H_0: \bar x =375\\H_a: \bar x

(Left tailed test at 5% level)

Since sample size is small though sigma is known we use Z test, since norm

Mean difference = -5

Std error = \frac{8}{\sqrt{8} } =2.828

Test statistic t = mean diference / std error = \frac{-5}{2.828} \\=-1.768

df = n-1 =5

p value = 0.063

7 0
3 years ago
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
3 years ago
Read 2 more answers
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