Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
I think the answer is either:
J.1/36 or G.1/100
Because 1 yard is 0.027778 inch. So it has to be a really small fraction.
Answer:
The distance between (-3, 2) and (0,3) is √10.
Step-by-step explanation:
As we go from (-3,2) to (0,3), x increases by 3 and y increases by 1.
Think of a triangle with base 3 and height 1. Use the Pythagorean Theorem to find the length of the hypotenuse, which represents the distance between the points (-3, 2) and (0, 3):
distance = √(3² + 1²) = √10
The distance between (-3, 2) and (0,3) is √10.
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we know that
When a rectangle with a width of 2.5 feet and a length of 8 feet rotates it makes a cylinder with a radius r = 2.5 ft and a height h = 8 ft
volume of a cylinder=pi*r²*h-----> pi*2.5²*8----> 157 ft³
the answer is157 ft³
Factor the expression:
-1/6*6(x-2y)
Divide by 6
-1(x-2y)
Then times by -1
-x+2y
Is your answer
Hope this helps
