Answer:
(-∞ , -6] ∪ [6 , +∞)
Step-by-step explanation:
<u>Let D be the domain of f </u>.
D = {x ∈ IR ; where x² - 36 ≥ 0}
x² - 36 ≥ 0
⇔ x² ≥ 36
⇔ x² ≥ 6²
⇔ √(x²) ≥ √(6²)
⇔ |x| ≥ 6
⇔ x ∈ (-∞ , -6] ∪ [6 , +∞)
Answer:


Step-by-step explanation:
By geometric mean property:

Step-by-step explanation:
The square root of 3 is the positive real number that, when multiplied by itself, gives the number 3. It is denoted mathematically as √3. It is more precisely called the principal square root of 3, to distinguish it from the negative number with the same property. The square root of 3 is an irrational number.

<em><u>Solution:</u></em>
Given that we have to find the sum of 
<em><u>Let us first convert the mixed fractions to improper fractions</u></em>
Multiply the whole number part by the fraction's denominator.
Add that to the numerator.
Then write the result on top of the denominator
Therefore,

Now we can add both the fractions

Make the denominators same

Now convert the fraction to mixed number
When we divide 53 by 10 , the remainder is 3
Therefore, write 5 as a whole number and and 3 as numerator and 10 as denominator

Thus the sum of given mixed fraction is 