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Ksenya-84 [330]
3 years ago
5

Simplify 2(3x+7)-4(7+x)

Mathematics
1 answer:
professor190 [17]3 years ago
7 0

Answer:

\boxed{ \bold { \huge{ \boxed{ \sf{2x - 14}}}}}

Step-by-step explanation:

\sf{2(3x + 7) - 4(7 + x)}

Distribute 2 through the parentheses

⇒\sf{6x + 14 - 4(7 + x)}

Distribute 4 through the parentheses

⇒\sf{6x + 14 - 28 - 4x}

Collect like terms

⇒\sf{6x - 4x + 14 - 28}

⇒\sf{2x + 14 - 28}

Calculate

⇒\sf{2x - 14}

Hope I helped!

Best regards!!

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3 years ago
Which one is correct? Please hurry <3
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3 years ago
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Sophia finished 2/3 of a book. She calculated that she finished 90 more pages than she has yet to read. How long is her book?
TEA [102]

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The book is 270 pages long.

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2 years ago
Solve b=y-my for y.
Mrrafil [7]

Answer:

y = \frac{b}{1-m}

Step-by-step explanation:

In order to get <em>y</em> by itself, we need to pull <em>y</em> out of 1 and <em>m </em>on the right side.

b = y(1 - m) since y(1 - m) is the same as y - my.

Once we have pulled <em>y</em> out of 1 and m, we can divide both sides by 1 - m

\frac{b}{1 - m} = \frac{y(1 - m)}{1 - m}

We can cancel out the 1 - m on the right side since (1 - m) / (1 - m) = 1

Finally we get our answer:

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2 years ago
Peter's farm has 160 meters of fencing, and he wants to fence a rectangular field thatborders a straight river. He needs no fenc
Likurg_2 [28]

ANSWER

3200 m²

EXPLANATION

Peter wants to build a fence around a rectangular field, except for one side because the river is there,

So, the total perimeter of the fence is,

P=W+W+L=2W+L

And this is equal to 160 m. Solving for L,

160=2W+L\text{ }\Rightarrow\text{ }L=160-2W

The area of this field is,

A=WL

Replace L with the expression we found from the perimeter,

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The area is given by a quadratic function whose leading coefficient is negative, which means that the graph is a downward parabola and, therefore, the vertex is the maximum value of the area.

The x-coordinate of the vertex is given by,

f(x)=ax^2+bx+c\text{ }\Rightarrow\text{ }x_{vertex}=\frac{-b}{2a}

In this case, x is W, a = -2, and b = 160, so the width of the field for the maximum area is,

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Hence, the largest area of Peter's farm that can be fenced is 3200 square meters.

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11 months ago
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