What is the slope of a line that is parallel to the line -6y=8x-4?
1 answer:
Answer:
<u>-4</u>
3
Step-by-step explanation:
-6y=8x-4
0=8x+6y-4---(i)
slope (m1)=<u>-coefficient</u><u> </u><u>of</u><u> </u><u>x</u>
coefficient of y
=<u>-8</u>
6
= <u>-4</u>
3
As the lines are parallel,
m1=m2
so,
The slope of line parallel to the line having equation -6y=8x-4 is <u>-4</u>
3
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