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Oksana_A [137]
2 years ago
13

Sup peeps Can someone find the area of this plz

Mathematics
1 answer:
ziro4ka [17]2 years ago
7 0

Answer:

<h2><em><u>448</u></em><em><u> </u></em><em><u>sq.ft</u></em></h2>

Step-by-step explanation:

The following figure is a <em><u>trapezium</u></em><em><u>, </u></em>

<em><u>So</u></em><em><u> </u></em><em><u>Given</u></em><em><u>,</u></em>

Parallel sides of the trapezium = 17ft and 39ft

Height of the trapezium = 16ft

<em><u>Therefore</u></em><em><u>, </u></em>

Area of the trapezium

=  \frac{1}{2}  \times (sum \: of \: parallel \: sides) \times height

=  \frac{1}{2}  \times (17ft + 39ft) \times 16ft

=  \frac{1}{2}  \times 56ft \times 16ft

= 56ft \times 8ft

= 448 {ft}^{2}

<em><u>Hence</u></em><em><u>,</u></em>

<em><u>448</u></em><em><u> </u></em><em><u>sq.ft</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>trapezium</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

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Answer:

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a ship leaves port on a bearing of 44.0 degrees, and travels 11.4 mi. the ship turns east and travels 6.2 mi. How far is the shi
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Based on the information provided, \overrightarrow{r} = at a bearing angle of = 59.88° .

We are requested to calculate the overall displacement of the ship, both in magnitude and direction, once it departs the harbor under the stated parameters. First, let's define a bearing.

<h3>What is bearing in the context given above?</h3>

Angles are generally measured anticlockwise from the positive x-axis, whereas bearing angles are evaluated clockwise from the positive y-axis. A bearing is NOT a standard angle measuring tool.

Therefore, a bearing of 44.0° indicates that this is an angle 90.0° - 44.0° = 46°. This is the angle to be used in the calculations.

We're given that the first displacement is 11.4° at an angle of 46° (which was computed earlier).

Step 1  - Split the above into components

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The second displacement is a simple 6.2mi due east, that is, the positive

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The direction of the displacement vector is given by:

tan Ф = (Δy)/(Δx)

= arctan (8.2/14.12)

= arctan (0.5807365439)

= 30.12°

Recall that we were asked for the bearing angle. The bearing angle is what we get when we subtract 30.12° from 90°.

That is:
= 90 - 30.12

= 59.88°

Learn more about bearing angle:
brainly.com/question/22719608
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