Answer:
<h2><em><u>448</u></em><em><u> </u></em><em><u>sq.ft</u></em></h2>
Step-by-step explanation:
The following figure is a <em><u>trapezium</u></em><em><u>, </u></em>
<em><u>So</u></em><em><u> </u></em><em><u>Given</u></em><em><u>,</u></em>
Parallel sides of the trapezium = 17ft and 39ft
Height of the trapezium = 16ft
<em><u>Therefore</u></em><em><u>, </u></em>
Area of the trapezium
![= \frac{1}{2} \times (sum \: of \: parallel \: sides) \times height](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20%28sum%20%5C%3A%20of%20%5C%3A%20parallel%20%5C%3A%20sides%29%20%5Ctimes%20height)
![= \frac{1}{2} \times (17ft + 39ft) \times 16ft](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20%2817ft%20%2B%2039ft%29%20%5Ctimes%2016ft)
![= \frac{1}{2} \times 56ft \times 16ft](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%2056ft%20%5Ctimes%2016ft)
![= 56ft \times 8ft](https://tex.z-dn.net/?f=%20%3D%2056ft%20%5Ctimes%208ft)
![= 448 {ft}^{2}](https://tex.z-dn.net/?f=%20%3D%20448%20%7Bft%7D%5E%7B2%7D%20)
<em><u>Hence</u></em><em><u>,</u></em>
<em><u>448</u></em><em><u> </u></em><em><u>sq.ft</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>trapezium</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>