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3 years ago

A. Spreads the hourly earnings for career B are more spread out.

Mathematics

1 answer:

vitfil [10]3 years ago

6 0

Answer:

Attached below are the answers.

Step-by-step explanation:

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NEED HELP ASAP!! Angles of Elevation and Despression! Need to find x! Round to the nearest tenth!

Oksi-84 [34.3K]

Answer:

Hey there!

Sine 61=x/500

Sine 61(500)=x

x=437.3

Let me know if this helps :)

3 0

4 years ago

Which equations are true for x = -2 and x = 2? Select two options

Flauer [41]

Answer:

A and C

Step-by-step explanation:

solving the equations

x² - 4 = 0 ( add 4 to both sides )

x² = 4 ( take square root of both sides )

x = ± $\sqrt{4}$ = ± 2 ← required solution

x² = - 4 ← has no real solutions

4x² = 16 ( divide both sides by 4 )

x² = 4 ( take square root of both sides )

x = ± $\sqrt{4}$ = ± 2 ← required solution

2(x - 2)² = 0 , then

x- 2 = 0 ( add 2 to both sides )

x = 2 ← not the required solution

5 0

2 years ago

Read 2 more answers

Choose the correct description of the graph of the inequality x − 3 greater than or equal to 5. i need to know closed or open an

Ghella [55]

The answer is x is greater than or equal to 8, so the line goes to the right with a closed circle.

8 0

3 years ago

If 2y^2+2=x^2, then find d^2y/dx^2 at the point (-2, -1) in simplest form.

horrorfan [7]

Answer:

$\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{1}{2}$

Step-by-step explanation:

We have the equation:

$2y^2+2=x^2$

And we want to find d²y/dx² at the point (-2, -1).

So, let's take the derivative of both sides with respect to x:

$\frac{d}{dx}[2y^2+2]=\frac{d}{dx}[x^2]$

On the left, let's implicitly differentiate:

$4y\frac{dy}{dx}=\frac{d}{dx}[x^2]$

Differentiate normally on the left:

$4y\frac{dy}{dx}=2x$

Solve for the first derivative. Divide both sides by 4y:

$\frac{dy}{dx}=\frac{x}{2y}$

Now, let's take the derivative of both sides again:

$\frac{d}{dx}[\frac{dy}{dx}]=\frac{d}{dx}[\frac{x}{2y}]$

We will need to use the quotient rule:

$\frac{d}{dx}[f/g]=\frac{f'g-fg'}{g^2}$

So:

$\frac{d^2y}{dx^2}=\frac{\frac{d}{dx}[(x)](2y)-x\frac{d}{dx}[(2y)]}{(2y)^2}$

Differentiate:

$\frac{d^2y}{dx^2}=\frac{(1)(2y)-x(2\frac{dy}{dx})}{4y^2}$

Simplify:

$\frac{d^2y}{dx^2}=\frac{2y-2x\frac{dy}{dx}}{4y^2}$

Substitute x/2y for dy/dx. This yields:

$\frac{d^2y}{dx^2}=\frac{2y-2x\frac{x}{2y}}{4y^2}$

Simplify:

$\frac{d^2y}{dx^2}=\frac{2y-\frac{2x^2}{2y}}{4y^2}$

Simplify. Multiply both the numerator and denominator by 2y. So:

$\frac{d^2y}{dx^2}=\frac{4y^2-2x^2}{8y^3}$

Reduce. Therefore, our second derivative is:

$\frac{d^2y}{dx^2}=\frac{2y^2-x^2}{4y^3}$

We want to find the second derivative at the point (-2, -1).

So, let's substitute -2 for x and -1 for y. This yields:

$\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{2(-1)^2-(-2)^2}{4(-1)^3}$

Evaluate:

$\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{2(1)-(4)}{4(-1)}$

Multiply:

$\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{2-4}{-4}$

Subtract:

$\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{-2}{-4}$

Reduce. So, our answer is:

$\frac{d^2y}{dx^2}_{(-2, -1)}=\frac{1}{2}$

And we're done!

7 0

3 years ago

POSSIBLE POINTS: 14.29

OverLord2011 [107]

Answer:

A = 112 , C = 85 , B = 90

Step-by-step explanation:

A + B + C = 287

A + C = 197

A + B = 202

C = 197 - A

B = 202 - A

A + 202 - A + 197 - A = 287

A = 112

C = 85

B = 90

8 0

3 years ago