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3 years ago

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The height of a trapezoid is 18 in. and its area is 96 in square. One base of the trapezoid is 6 inches longer than the other ba

se. What are the lengths of the base?Explain how you found your answer

1 answer:

ale4655 [162]3 years ago

3 0

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A middle school took all of its 6th grade students on a field trip to see a symphony at

butalik [34]

Answer:

49%

Step-by-step explanation:

to get the percentage you put the number of occupied seats over total number of seats and multiply it by 100 over 1

4 0

3 years ago

A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha

ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students received a passing grade = 77%

n = sample of tests = 40

p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<u>99% confidence interval for p</u> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ , $0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ ]

= [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0

2 years ago

Please help ASAP!<br><br> What is m∠CAD?<br> a.) 25º<br> b.) 90º<br> c.) 100º<br> d.) 115º

mars1129 [50]

<span>m∠CAD = 90 + 25 = 115
answer
</span><span>d.) 115º</span>

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2 years ago

Read 2 more answers

Tell whether the angles are complementary or supplementary. Then find the value of x.

Lady bird [3.3K]

Answer:

complementary x=5

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

JUST THE FIRST ONE EASY PLS ASAP

Sladkaya [172]

Answer:

<h2>For the first triangle, <u>x equals 22cm.</u></h2>

Here's how:-

x is the altitude or height of the triangle. To find it, we can use the Pythagoras theorem:-

$altitude^{2} + base^{2} = hypotenuse^{2}$

The base is 120cm and the hypotenuse is 122cm

Putting this in the equation, we get:-

$altitude^{2} + 120^{2} = 122^{2}$

$altitude^{2} = 122^{2}- 120^{2}$

$altitude^{2} = 14884 - 14400$

$altitude^{2}$ = 484

altitude = $\sqrt{484}$

<h3>altitude = 22cm</h3><h2><u>So, x = 22cm</u></h2>

7 0

2 years ago